问题描述
为了加快启动项目的速度，我创建了一个小的bash脚本，该脚本执行以下操作:
To speed up launching projects I created a small bash script which does the following:
- 接受参数(项目名称)
- 移动到该项目的目录
- 启动虚拟环境
- 启动Jupyter笔记本
#!/bin/bash
if [ "$1" == "k3" ]; then
project_path="tau-code/k3-analysis/"
fi
codepath="/media/peter/somedrive/code"
full_path="$codepath/$project_path"
# Go to directory of project
cd $full_path
# Start environment & notebook if available
pipenv shell
jupyter notebook --ip=0.0.0.0
它会激活环境，但不会运行jupyter命令.当我退出环境时，我看到错误:
It activates the environment, but does not run the jupyter command. When I exit the environment I see the error:
我可以在新创建的环境中手动键入jupyter notebook --ip=0.0.0.0，并且可以正常工作.
I can manually type jupyter notebook --ip=0.0.0.0 in my newly created environment and that does work.
可能是什么问题?
推荐答案
pipenv shell启动一个新的shell，必须使用exit将其禁用.在脚本中，调用pipenv shell之后的任何命令都不会在该新Shell中执行.相反，它们在关闭虚拟环境外壳程序后在同一bash外壳程序中执行.您应该使用pipenv run jupyter notebook --ip=0.0.0.0
pipenv shell starts a new shell which must be deactivated by using exit. In your script any commands following the call to pipenv shell are not executed in that new shell. Instead they are executed in the same bash shell after the virtual environment shell is closed. You should use pipenv run jupyter notebook --ip=0.0.0.0
请参见 pipenv文档:
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