在方法中使用OUT

问题描述

  static void Main(string[] args)
        {
            Console.WriteLine("Choose 1 to continue or 0 to exit");
            int choice = int.Parse(Console.ReadLine());
            if (choice==0)
            {
                Console.WriteLine("Bye");
                System.Environment.Exit(0);
            }
            do
            {

                Check(out float i,"MEssage");
                Check(out float j,"MEssage");
                Check(out float k,"MEssage");

            } while (choice==1);
        }

        public static void Check(out float param, string message)
        {
            bool isNumber;
            string input;
            do
            {
                input = Console.ReadLine();
                isNumber = float.TryParse(input, out param);
            } while (!isNumber);
        }
}

我的尝试：



我试图只检查一次用户输入，然后将其作为方法调用，如果错误则不让用户继续，但是在调用方法时出现错误。我无法完全理解方法中OUT的用法。

What I have tried:

I am trying to check users input only once and then call it as a method and not letting the user to continue if it is wrong but when calling the method there is an error. I can not fully understand the usage of OUT in methods.

推荐答案

float i, j, k;
Check(out i,"MEssage");
Check(out j,"MEssage");
Check(out k,"MEssage");

// Now you can use i, j and k...

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