问题描述
我正在使用来创建显示一堆信息的仪表板的小部件。我已经成功实现了它,因此显示了1个图表,并使用了一些块逻辑来一次显示2个小部件。这一切都很好,但是我想增强一下功能:
I'm using Bootstrap's Carousel to create a dashboard that shows a bunch of Highcharts widgets. I've successfully implemented it so 1 chart shows up and used a bit of "chunking" logic to show 2 widgets at a time. This all works great, but I'd like to enhance things:
- 如果用户的屏幕尺寸足以容纳2张图表,显示2个图表并按2进行分页。
- 如果用户的小屏幕尺寸仅适合1个图表,则显示1并按1进行分页。
- 如果用户的屏幕尺寸< 2向上,但大于1,显示1.5图表并按1进行分页。
我正在使用AngularJS构建HTML。在单独的模板块中执行#1和#2,然后根据屏幕尺寸进行显示/隐藏很容易。但是,我对#3有点困惑。我不知道如何显示2个图表,而只能按1分页。
I'm using AngularJS to build the HTML. It's easy enough to do #1 and #2 in separate template blocks and then show/hide based on screen size. However, I'm a bit stumped on #3. I can't figure out how to display 2 charts, but only paginate by 1.
推荐答案
我最终编写了以下JavaScript去做这个。基本上,我要渲染两个不同的部分(带有.oneup和.twoup类),然后如果显示.oneup,则添加一个预览。
I ended up writing the following JavaScript to do this. Basically, I'm rendering two different sections (with classes .oneup and .twoup) and then adding a "preview" if .oneup is displayed.
<script type="text/javascript">
var chartBar = $('#chart-bar');
function chartPreview(firstChart) {
var chartBarWidth = chartBar.width();
if (chartBarWidth > 600) {
var currentChart = $('.carousel-inner:visible .active');
// append the next widget to the current item
var chartToCheck = (firstChart) ? currentChart : currentChart.next();
if (chartToCheck.next()) {
chartToCheck.next().find('.widget').clone().appendTo(chartToCheck);
$('.carousel-inner').css({'margin-left': '10px', 'width': '98.8%'})
}
} else if (chartBarWidth > 1040) {
$('.carousel-inner').css({'margin-left': '0', 'width': '100%'})
}
}
$(document).ready(function() {
$('.widgets').sortable({
cursor: "move",
handle: ".heading"
}).disableSelection();
$('.boxes,.tasks').sortable();
var carousel = $('.carousel');
$(carousel).carousel({
interval: 0
});
if (chartBar.width() < 1040) {
chartBar.find('.oneup').show();
chartPreview(true);
carousel.bind('slide', function() {
chartPreview(false);
});
} else {
chartBar.find('.twoup').show();
}
});
如果我不必同时渲染oneup和twoup,但是我不确定如何使用AngularJS进行渲染。这是我的单次ng-repeat:
It'd be nice if I didn't have to render both oneup and twoup, but I'm not sure how to do that with AngularJS. Here's my oneup ng-repeat:
<div class="carousel-inner">
<div class="item chart"
ng-repeat="widget in widgets | filter: {type: 'chart'} | orderBy: 'order'"
ng-class="{active: $index == 0}">
<chart class="widget" value="{{widget}}" type="{{widget.chartType}}"></chart>
</div>
</div>
对比两次ng-repeat:
Versus the twoup ng-repeat:
<div class="carousel-inner">
<div class="item chart"
ng-repeat="widget in widgets | filter: {type: 'chart'} | chunk: 2 | orderBy: 'order'"
ng-class="{active: $index == 0}">
<chart class="widget" value="{{widget[0]}}" type="{{widget[0].chartType}}"></chart>
<chart class="widget" value="{{widget[1]}}" type="{{widget[1].chartType}}"></chart>
</div>
</div>
这篇关于Bootstrap Carousel,根据屏幕大小显示不同数量的项目的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!