Java，平均数字列表

问题描述

在下面的Java代码中，我的平均温度降低了1位小数.

In the following Java code, my average temperature is 1 decimal place off.

例如，而不是 69.0 ，而是 6.9 .

输入可以是任何10个数字.因此，可以说我输入了10个温度，每个温度为10度.10个输入的总数为100，因此平均值应为10，但我收到的平均值为1.0.

The input can be any 10 numbers. So lets say I input 10 temperatures and each 1 is 10 degrees. The total for the 10 inputs is 100, so the average should be 10 but instead I'm receiving an average of 1.0.

代码:

import java.util.Scanner;
public class NumberAboveAverage {
    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);
        final int TotalTemps = 10;
        double[] numbers = new double[TotalTemps];
        double sum = 0;
        double average = 0;
        double max = 0;
        for (int n = 0; n < numbers.length; n++) {
            System.out.print("Enter a temperature: ");
            numbers[n] = input.nextInt();

            if (numbers[n] > max) {
               max = numbers[n];
            }
            sum = numbers[n];
        }

        for (int i = 0; i < numbers.length; i++) {
            sum = numbers[i];
        }

        average = sum / 10;    //average is not an average of the numbers.
        System.out.println("Average temp = " + average);

        int count = 0;
        for (int i = 0; i < numbers.length; i++) {
            if (numbers[i] > average) {
               count++;
            }
        }
        System.out.println(count + " days were above average");
    }
}

推荐答案

您实际上并没有将数字求和.

You're not actually summing the numbers together.

应为 sum + =数字[i];

不是 sum =数字[i];

您似乎也尝试执行两次此操作，这是不必要的.

You also appear to be attempting to do this twice, which is unnecessary.

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