如何从XML字符串中读取XML

本文介绍了如何从XML字符串中读取XML的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

这是我的xml

This is my xml

<REPORT-FILE>
  <INQUIRY-STATUS>
    <INQUIRY>
      <INQUIRY-UNIQUE-REF-NO>006f000026EGk88JJFS99115740</INQUIRY-UNIQUE-REF-NO>
      <MBR-ID>NBF0000131</MBR-ID>
      <REQUEST-DT-TM>30-06-2015 17:13:51</REQUEST-DT-TM>
      <REPORT-ID>CAPR161018CR40279043</REPORT-ID>
      <RESPONSE-DT-TM>18-10-2016 11:23:25</RESPONSE-DT-TM>
      <RESPONSE-TYPE>ACKNOWLEDGEMENT</RESPONSE-TYPE>
    </INQUIRY>
  </INQUIRY-STATUS>
</REPORT-FILE>

我的尝试：

What I have tried:

XmlDocument doc = new XmlDocument();
       doc.LoadXml(dataPacket);

       //root of the xml <DATAPACKET>
       XmlElement root = doc.DocumentElement;
       //using xpath to get data I want https://msdn.microsoft.com/en-us/library/ms256115%28v=vs.110%29.aspx?f=255&MSPPError=-2147217396
       PacketRequestId = Int32.Parse(root.SelectSingleNode("@REQUEST-ID").InnerText);
       PacketReferenceNumber = Int32.Parse(root.SelectSingleNode("@REFERENCE-NO").InnerText);

       XmlNode responseType = root.SelectSingleNode(@"HEADER/RESPONSE-TYPE");
       HeaderResponseTypeCode = Int32.Parse(responseType.SelectSingleNode("@CODE").InnerText);
       HeaderResponseTypeDescription = responseType.SelectSingleNode("@DESCRIPTION").InnerText;

推荐答案

XmlDocument xmlDoc = new XmlDocument();
               
               xmlDoc.LoadXml(xmlstring);
               XmlNodeList nodeList = xmlDoc.DocumentElement.SelectNodes("REPORT-FILE/INQUIRY-STATUS/INQUIRY");

foreach (XmlNode node in nodeList)
{
string nodevalue= node.SelectSingleNode("INQUIRY-UNIQUE-REF-NO").InnerText;
}
                        {

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