C#Binarywriter写字符串

本文介绍了C#Binarywriter写字符串的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

你好，我打算用C#中的binarywriter将char写入二进制文件:

Howdy, I intend to write char to a binary file with binarywriter in C#:

FileStream filestream = new FileStream("test.t", FileMode.Create, FileAccess.Write, FileShare.Read, 1024);
      BinaryWriter binaryWriter = new BinaryWriter(filestream);
      binaryWriter.Write("hello");
      binaryWriter.Write("AAA");
      binaryWriter.Close();
      file.Close();

但是，当我检查输出文件时，我发现每个字符串的前面都有多余的字节，因此，hello变成了六个字符: 0x05''h''''e''''l''''l ''''o''和"AAA"变成四个字符: 0x03''A''''A''''A''

有人知道为什么吗?

VS 2008
在win7和xp中进行测试.

But when I exam the output file I found there are extra bytes in the front of each string, such that the hello become six chars: 0x05 ''h''''e''''l''''l''''o'' and "AAA" become four chars: 0x03''A''''A''''A''

Anyone know why?

VS 2008
Test in win7 and xp.

推荐答案

0x05  - number of characters in the string "hello"
'h'
'e'
'l'
'l'
'o'
0x03  - number of characters in the string "AAA"
'A'
'A'
'A'

您的应用程序中此版本的字符串以十个字符开头，而不是五个

The version of this in your application had a string of ten characters to start with, rather than five

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