问题描述
这件事真的让我很困惑，请原谅我的无知.
This thing really confuses me, pardon my ignorance.
我在这里有一个 var $name ，我想摆脱数字，我不希望其中包含任何数字.我的 preg_match() 是这样的:
I have a var $name in here that I want to be free from number, I don't want any digit to be included in it. My preg_match() is this:
var_dump(preg_match('/[^\d]/',$name));
测试用例:
$name = "213131"; // int(0)
$name = "asdda"; // int(1)
$name = "as232dda"; // int(1)
我想要的是第三种情况也是 int(0).
What I want is to have the third case to be int(0) too.
我真的很难理解这个 preg_match()，文档说如果模式匹配主题，它返回 1.在我的例子中，我使用了一个否定类.
I'm really a hard time understanding this preg_match(), docs say it return 1 if a pattern match a subject. Here in my case, I use a negated class.
推荐答案
#3 匹配，因为您有字母和数字.你的英文正则表达式基本上是
#3 matches because you have both letters and numbers. Your regex in English basically says
如果有非数字字符则匹配
如果你想匹配只非数字字符，你必须让正则表达式匹配整个字符串并允许任意数量的字符:
If you want to match only non-digit characters, you have to have the regex match against the entire string and allow for an arbitrary number of characters:
^[^\d]+$
这篇关于`preg_match` PHP 中的整个字符串的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！