shell实现除法，保留小数点后N位

$more get_wstts_success.sh

#!/bin/bash

open_gw_1=$(ssh admin@open-gw- "sh /home/admin/bin/check_wstts_success.sh")

open_gw_2=$(ssh admin@open-gw- "sh /home/admin/bin/check_wstts_success.sh")

#echo $open_gw_1

#echo $open_gw_2

gw_1_all=$(echo $open_gw_1 | cut -d " " -f1)

gw_1_err=$(echo $open_gw_1 | cut -d " " -f2)

#echo $gw_1_all

#echo $gw_1_err

gw_2_all=$(echo $open_gw_2 | cut -d " " -f1)

gw_2_err=$(echo $open_gw_2 | cut -d " " -f2)

#echo $gw_2_all

#echo $gw_2_err

if [ $gw_1_all -eq  ] && [ $gw_2_all -eq  ]; then

    echo 1.00000

else

    successrate=$(echo "scale=5;rate=($gw_1_all + $gw_2_all - $gw_1_err - $gw_2_err) / ($gw_1_all + $gw_2_all);if(length(rate)==scale(rate)) print ;print rate"|bc)

    echo $successrate

fi

第二种实现方法：

awk 'BEGIN{printf "%0.6f",5/6}'