函数中的静态变量不适用于C而是C ++

问题描述

好的......这个问题让我发疯了......

但代码很简单，我确实已经谷歌了。



代码：

Okay...This problem is driving me crazy...
but the code is pretty easy, and I did already google it.

Code :

void f(int c) {
	static int foo = c;
}

这是我用Google搜索的ed



[]



它表示C中的静态与'C ++'相当。

但我的编译器只是继续说

Here is what I googled"ed"

Difference between static in C and static in C++?? - Stack Overflow[^]

It says static in C is 'equalvalent to' C++.
but my compiler just keep saying

"Initializer element is not constant"

和我也谷歌它，它只是一直在说常量问题....

但是'const'不是我想要的，我只需要保留变量'foo'！



我尝试过：



Google

and also I did google it, it just keeps saying the 'constant' problem....
but 'const' is not what I want, I just need to reserve the variable 'foo' !

What I have tried:

Google

推荐答案

void f(int c) {
    static int foo = 0;
    foo = c;
}

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