如何用它的名称实例化一个类？提前阅读我的文字......

本文介绍了如何用它的名称实例化一个类？提前阅读我的文字......的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述 大家好：D 我有一个包含类名的字符串。 我想从该类中实例化： string strategyNameStr; 策略*策略; //以下所有类都来自策略。 //和" strategyNameStr"""包含以下类之一的 之一的名称。 //例如 strategyNameStr = _T（" SimpleStrategy"）; SimpleStrategy * simStrategy; MiddleStrategy * midStrategy; HighStrategy * highStrategy; 如何我可以使用" strategyNameStr"""在下一行...... 策略=新的？ 或 有没有解决方案？ 谢谢。 解决方案 ba ******** @ yahoo.com 写道： 我有一个包含名称的字符串一个班级。 我想从该班级实例化： string strategyNameStr; 策略*策略; //以下所有类都来自策略。 //和" strategyNameStr"""包含以下类之一的 之一的名称。 //例如 strategyNameStr = _T（" SimpleStrategy"）; SimpleStrategy * simStrategy; MiddleStrategy * midStrategy; HighStrategy * highStrategy; 如何我可以使用" strategyNameStr"""在下一行...... 策略=新的？ 或 有什么解决方案吗？ #define INSTANTIATE_BY_NAME（var，str，clazz）\ if（str == #clazz）var = new clazz 策略= 0; INSTANTIATE_BY_NAME（策略，strategyNameStr，SimpleStrategy）; if（！strategy） INSTANTIATE_BY_NAME（策略，strategyNameStr，MiddleStrategy）; if（！策略） INSTANTIATE_BY_NAME（策略，策略名称，高级策略）; 或类似的东西。 V - 请在回复时删除资金''A'通过电子邮件 我没有回复最热门的回复，请不要问 2007-12-12 15 ：48：47-505，Victor Bazarov < v。******** @ comAcast.netsaid： > #define INSTANTIATE_BY_NAME（var，str ，clazz）\ if（str == #clazz）var = new clazz 你不需要Java-拼写错误的类型。 预处理器不关心关键字。 - Pete Roundhouse咨询有限公司（ www.versatilecoding.com ）的作者标准C ++库扩展：教程和参考 （ www.petebecker.com/tr1book ） Pete Becker写道： 在2007-12-12 15:48:47 -0500，Victor Bazarov < v。******** @ comAcast.netsaid： >> #define INSTANTIATE_BY_NAME（var，str，clazz）\ if（str == #clazz）var = new clazz 你不需要Java拼写错误的拼写错误。 预处理器并不关心关键字。 我的编辑器。 V - 请在通过电子邮件回复时删除资金''A' 我没有回复最热门的回复，请不要问 Hi everybody:D I''ve a string that contains the name of a class.I want to instantiate from that class: string strategyNameStr;Strategy * strategy; // All of the following classes are derived from Strategy.// and """ strategyNameStr """ contains the name of one of thefollowing classes.// e.g.strategyNameStr = _T( "SimpleStrategy" ); SimpleStrategy * simStrategy;MiddleStrategy * midStrategy;HighStrategy * highStrategy; How can I use """ strategyNameStr """ in the next line...strategy = new ? orIs there at all any solution? Thanks. 解决方案 ba********@yahoo.com wrote:I''ve a string that contains the name of a class.I want to instantiate from that class:string strategyNameStr;Strategy * strategy;// All of the following classes are derived from Strategy.// and """ strategyNameStr """ contains the name of one of thefollowing classes.// e.g.strategyNameStr = _T( "SimpleStrategy" );SimpleStrategy * simStrategy;MiddleStrategy * midStrategy;HighStrategy * highStrategy;How can I use """ strategyNameStr """ in the next line...strategy = new ?orIs there at all any solution?#define INSTANTIATE_BY_NAME(var, str, clazz) \if (str == #clazz) var = new clazz strategy = 0;INSTANTIATE_BY_NAME(strategy, strategyNameStr, SimpleStrategy);if (!strategy)INSTANTIATE_BY_NAME(strategy, strategyNameStr, MiddleStrategy);if (!strategy)INSTANTIATE_BY_NAME(strategy, strategyNameStr, HighStrategy); or something like that. V--Please remove capital ''A''s when replying by e-mailI do not respond to top-posted replies, please don''t askOn 2007-12-12 15:48:47 -0500, "Victor Bazarov" <v.********@comAcast.netsaid: >#define INSTANTIATE_BY_NAME(var, str, clazz) \ if (str == #clazz) var = new clazz You don''t need that Java-esque ugliness of misspelling class. Thepreprocessor doesn''t care about keywords. --PeteRoundhouse Consulting, Ltd. (www.versatilecoding.com) Author of "TheStandard C++ Library Extensions: a Tutorial and Reference(www.petebecker.com/tr1book) Pete Becker wrote:On 2007-12-12 15:48:47 -0500, "Victor Bazarov"<v.********@comAcast.netsaid:>>#define INSTANTIATE_BY_NAME(var, str, clazz) \ if (str == #clazz) var = new clazz You don''t need that Java-esque ugliness of misspelling class. Thepreprocessor doesn''t care about keywords.My editor does. V--Please remove capital ''A''s when replying by e-mailI do not respond to top-posted replies, please don''t ask 这篇关于如何用它的名称实例化一个类？提前阅读我的文字......的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！