本文介绍了如何通过递归获取数字列表的总和?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我想用递归函数对数字求和,即
I want to sum numbers with a recursive function, i.e.
getSum([1, 2, 3, 4, 5])
应该返回 1+2+3+4+5 == 15
should return 1+2+3+4+5 == 15
我不是递归函数方面的专家,我尝试过类似的方法:
I'm not an expert in recursive functions, I've tried something like:
def getSum(piece):
for i in piece
suc += getSum(i)
问题是我不能遍历整数.我确信这是一项非常简单的任务,但我真的无法弄清楚.
The problem is that I can't loop through integers. I'm sure this is a quite easy task but I really can't figure it out.
推荐答案
你不需要循环.递归会为您做到这一点.
You don't need to loop. Recursion will do that for you.
def getSum(piece):
if len(piece)==0:
return 0
else:
return piece[0] + getSum(piece[1:])
print getSum([1, 3, 4, 2, 5])
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