本文介绍了PHP MYSQL 显示打开状态的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我需要修改此脚本以仅显示打开记录.字段称为 statusRP
I need to amend this script to only show Open records. Field is called statusRP
$result = mysql_query("select id, ref, company, title, forename,
surname, tel, fax, mob, statusRP, email
from Client");
if (!$result) {
die("Query to show fields from table failed");
}
$fields_num = mysql_num_fields($result) ;
推荐答案
据我了解,
$result = mysql_query("select id, ref, company, title, forename, surname, tel, fax, mob, statusRP, email from Client WHERE Client.statusRP = 'Open'";)
还有一件事,使用 mysqli 而不是 mysql(如果 mysql 不是您的要求).我认为它会起作用.
One more thing, Use mysqli rather then mysql (if mysql is not your requirement). I think it will be work.
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