本文介绍了Java脚本中的下拉列表-trskaran的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
<html>
<head>
<script type="text/javascript">
function setOptions(chosen, selbox) {
selbox.options.length = 0;
if (chosen == " ") {
selbox.options[selbox.options.length] = new Option('Please select one of the options above first',' ');
}
if (chosen == "1") {
selbox.options[selbox.options.length] = new Option('--Select--','');
for($i=1; $i<=5; $i++)
{
$a=$i+10;
selbox.options[selbox.options.length] = new Option($a,$a);
}
}
if (chosen == "2") {
selbox.options[selbox.options.length] = new Option('--Select--','');
for($i=1; $i<=5; $i++)
{
$a=$i+20;
selbox.options[selbox.options.length] = new Option($a,$a);
}
}
if (chosen == "3") {
selbox.options[selbox.options.length] = new Option('--Select--','');
for($i=1; $i<=5; $i++)
{
$a=$i+30;
selbox.options[selbox.options.length] = new Option($a,$a);
}
}
if (chosen == "4") {
selbox.options[selbox.options.length] = new Option('--Select--','');
for($i=1; $i<=5; $i++)
{
$a=$i+40;
selbox.options[selbox.options.length] = new Option($a,$a);
}
}
if (chosen == "5") {
selbox.options[selbox.options.length] = new Option('--Select--','');
for($i=1; $i<=5; $i++)
{
$a=$i+50;
selbox.options[selbox.options.length] = new Option($a,$a);
}
}
}
</script>
</head>
<body>
<form name="myform">
<select name="optone" önChange="setOptions(document.myform.optone.options[document.myform.optone.selectedIndex].value,document.myform.opttwo);">
<option value=" " selected="selected">-------- Select --------</option>
<script type="text/javascript">
for($i=1; $i<=5; $i++)
{
document.write("<option value="+$i+">"+$i+"</option>")
}
</script>
</select>
<select name="opttwo">
<option value=" " selected="selected">Please select one of the options above first</option>
</select>
</form>
</body>
</html>推荐答案
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