本文介绍了如何在回发后显示模型PopUp?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
Hi guys ..
model pop up is dissapears after any post back .? . in this i hav one drop down list if i select any item in drop down Modal Popup disappears .
<form id="form1" runat="server">
<asp:ToolkitScriptManager ID="ToolkitScriptManager1" runat="server">
</asp:ToolkitScriptManager>
<div>
<asp:Panel ID="pnModelPopup" runat="server" CssClass="popup">
<table>
<tr>
<td>
User Name:
</td>
<td>
<asp:TextBox ID="txtUserName" runat="server"></asp:TextBox>
</td>
</tr>
<tr>
<td>
<asp:Button ID="btnCancel" runat="server" Text="Cancel" />
</td>
</tr>
<tr>
<td>
<asp:DropDownList runat="server" ID="drp" AutoPostBack="True"
onselectedindexchanged="drp_SelectedIndexChanged">
<asp:ListItem>a</asp:ListItem>
<asp:ListItem>a</asp:ListItem>
</asp:DropDownList>
</td>
</tr>
</table>
</asp:Panel>
<asp:ModalPopupExtender ID="ModalPopupExtender1" runat="server" PopupControlID="pnModelPopup"
TargetControlID="lnkbtnSignin" DropShadow="true" BackgroundCssClass="modalBackground"
PopupDragHandleControlID="pnModelPopup" OnOkScript="onOk()">
</asp:ModalPopupExtender>
<div style="margin-removed 300px">
<asp:LinkButton ID="lnkbtnSignin" runat="server">Sign in</asp:LinkButton>
</div>
</div>
</form>
please tell me guys how to show model pop up after post back . . please help me
thank u. .
推荐答案
protected void Page_Load(object sender, EventArgs e)
{
if (IsPostBack)
ModalPopupExtender1.Show();
}
protected void btnCancel_Click(object sender, EventArgs e)
{
ModalPopupExtender1.Hide();
}
包含以下代码。
Include the following codes.
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