本文介绍了HTML5文档中的简短脚本不起作用的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

脚本不起作用.我想在单击"nombreDeLista"时使"tiposDeFrutas"与显示属性可见.我还添加了CSS文档. ................................................... ................................................... ................................................... ......................

Script doesn''t work. I want to make "tiposDeFrutas" visible with display attribute when I click over "nombreDeLista". I also add the CSS document. ............................................................................................................................................................................

<pre lang="HTML"><!DOCTYPE html>
<html>
<head>
<title>Pruebas HTML</title>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<link rel=StyleSheet href="newcss.css" type="text/css" media=screen>
<script>
document.onload = function () {
document.getElementById("nombreDeLista").onclick = function () {
document.getElementsByClassName("tiposDeFrutas").style.display = "block";
};
};
</script>
</head>
<body>
<div id="nombreDeLista">Frutas</div>
<div class="tiposDeFrutas">Pera</div>
<div class="tiposDeFrutas">Limón</div>
</body>
</html>
____________________

.tiposDeFrutas {
display: none;
}



我尝试过的事情:

................................................... ................................................... ................................................... ...................................



What I have tried:

................................................................................................................................................................................

推荐答案

window.onload = function () {
      document.getElementById("nombreDeLista").onclick = function () {
         var arr = document.getElementsByClassName("tiposDeFrutas");
         for (var i = 0; i < arr.length; i++) {
            arr[i].style.display = 'block';
         }
      }
   }


这篇关于HTML5文档中的简短脚本不起作用的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

10-24 18:35