本文介绍了如何对表的行和列求和的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
id fes bus snacks other total
=============================================
1 400 200 50 20 670
=============================================
2 350 100 20 0 470
==============================================
TOTAL = 750 300 70 290 1140
=============================================
pls how can i create this kind of table? where id=1 has its total at the end of the row e.g id=1 has 400 + 200 + 50 + 20 = 670 and also fees has its total at the end of its the column e.g 400 + 350 = 750
and this should apply to all the table records i will appreciate html, php and sql codes,i am a learner thanks
<pre>
<pre>am so new here! pls pardon my english,
我的尝试：
What I have tried:
<table width="100%">
<tr>
<th >S/N</th>
<th>fes</th>
<th>bus</th>
<th>snacks</th>
<th>other</th>
<th>total</th>
</tr>
<?php
$conn=mysqli_connect('localhost','root','','practice');
$table=mysqli_query($conn,'SELECT * FROM `try`');
while($row=mysqli_fetch_array($table))
{
$id=$row['id'];
$date=$row['fes'];
$salary=$row['bus'];
$recurrent=$row['snacks'];
$repairs_maint=$row['other'];
$creditors=$row['total'];
?>
<tr>
<td class="sno"><?php echo $id ?></td>
<td class="mark"><?php echo $fes ?></td>
<td class="mark"><?php echo $bus ?></td>
<td class="mark"><?php echo $snacks?></td>
<td class="mark"><?php echo $other?></td>
<td class="mark"><?php echo $total?></td>
<?php } ?>
<?php
$add=mysqli_query($conn,'SELECT SUM(fes),SUM(bus),SUM(snacks),SUM(other) ,SUM(total) FROM `try`');
while($row1=mysqli_fetch_array($add))
{
$mark=$row1['SUM(fes)'];
$mark1=$row1['SUM(bus)'];
$mark3=$row1['SUM(snacks)'];
$mark4=$row1['SUM(other)'];
$mark5=$row1['SUM(total)'];
?>
<tr>
<tr></tr>
<th>Total =</th>
<td><?php echo $mark ?></td>
<td><?php echo $mark1 ?></td>
<td><?php echo $mark3 ?></td>
<td><?php echo $mark4 ?></td>
<td><?php echo $mark5 ?></td>
<?php } ?>
</table>
Please i will appreciate your own code in html,php and sql thanks</pre
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