当搜索到的字符串不存在时，Jenkins Shell脚本返回退出代码1

问题描述

我正在詹金斯(Jenkins)尝试以下内容，目的是搜索工作失败中的一连串错误.
这将每天运行.

I'm tring the following at Jenkins in aim to search strings of failures in jobs.
This will run on daily basis.

def sd = "2020" + "${env.START_DATE}" + "0000"
def ed = "2020" + "${env.END_DATE}" + "2359.59"

pipeline {
    agent {label "master"}
    stages {
        stage('Build') {
            steps {

                print(sd)
                sh 'echo "Hello World"'
                sh """
                    pwd
                    #rm end-time start-time
                    #rm $WORKSPACE/$PARSING_OUTPUT
                    touch -t $sd $WORKSPACE/start-time
                    touch -t $ed $WORKSPACE/end-time
                    find /var/lib/jenkins/jobs/. -type f -newer $WORKSPACE/start-time  ! -newer $WORKSPACE/end-time -name '*' -exec grep $SEARCH_STRING /dev/null {} + >> $WORKSPACE/$PARSING_OUTPUT
                    ls -ltr
                """
            }
        post {
                always {
                    echo "sending mail"
                    //mail to: '[email protected]',
                    //subject: "Parse Jenkins log",
                    //body: "TBD"
                    //body: "${env.BUILD_URL} has result ${currentBuild.result}"
                }
            }
        }
    }
}

我的问题是，如果我要查找的字符串不存在.工作失败了.
控制台输出显示ERROR: script returned exit code 1.
我尝试添加#!/bin/sh，使我可以不执行任何选项-并没有帮助.
有什么建议吗?

My problem is that if the string I'm looking for isn't exsist. the job fail..
Console output display ERROR: script returned exit code 1.
I tried adding #!/bin/sh that will allow me to execute with no option - didn't help.
any suggestions ?

推荐答案

有多种方法可以实现上述目标

There are multiple way to achive above

1)使用set + e#禁止非零退出

1) use set +e # Disable exit on non-zero

设置+ e

..

'''

2)使用OR ||使用cmd

2) use OR || with cmd

$ CMD ||回声字符串不存在."

$CMD || echo "string doesn't exist."

'''

3)如下使用

脚本:您的脚本"，

returnStatus:true)

returnStatus: true )

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