问题描述
继续，，我如何按周分页？
In continuation of my struggle with WeekArchiveView, how do I paginate it by week?
我想要的是：
- 知道是否有下一个/上一个一周可用;
- 如果有，提供模板中的链接。
我'd喜欢也可以跳过空周。
I'd like it to also skip empty weeks.
显示 get_next_day / get_prev_day 和 get_next_month / get_prev_month 可用，但几周没有。
The source shows get_next_day / get_prev_day and get_next_month / get_prev_month are available, but nothing for weeks.
推荐答案
这是非常有趣的。确定 MonthMixin 包括 get_next_month / get_prev_month 方法， code> DayMixin 包含 get_next_day / get_prev_day 方法。但是，YearMixin和WeekMixin在定义中都没有功能上的等价物。似乎有点像Django团队的一个监督。
That is definitely interesting. Sure enough MonthMixin includes get_next_month/get_prev_month methods, and DayMixin includes get_next_day/get_prev_day methods. However, both YearMixin and WeekMixin have no functional equivalent in their definitions. Seems like a bit of an oversight on the Django team's part.
我认为你最好的选择是将WeekArchiveView或BaseWeekArchiveView子类化（如果最终可能要更改响应格式，并且不想重新实现您的方法）并添加您自己的 get_next_week / get_prev_week 方法。然后让你的视图继承自你的子类。一个简单的修改 DayMixin 的方法应该是足够的。
I think your best bet is to subclass either WeekArchiveView or BaseWeekArchiveView (if you may eventually want to change up the response format and don't want to have to re-implement your methods) and add your own get_next_week/get_prev_week methods. Then have your view inherit from your subclass instead. A simple modification of DayMixins methods should be sufficient.
def get_next_week(self, date):
"""
Get the next valid week.
"""
next = date + datetime.timedelta(days=7)
return _get_next_prev_month(self, next, is_previous=False, use_first_day=False)
def get_previous_week(self, date):
"""
Get the previous valid week.
"""
prev = date - datetime.timedelta(days=7)
return _get_next_prev_month(self, prev, is_previous=True, use_first_day=False)
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