为什么我得到不同的Htt presponse比Android的浏览器？

问题描述

我想从这个URL简单的HTTP响应：http://realtorsipad.demowebsiteonline.net/eventsfeed.php

但意外的是没有返回，而另一返回的HTML页面预期的XML响应！

我不能够理解什么是问题。

下面是示例活动：

 公共类MainActivity1延伸活动{
    字符串parsingWebURL =htt​​p://realtorsipad.demowebsiteonline.net/eventsfeed.php;
    串线=;
    文档docXML;    / **当第一次创建活动调用。 * /
    @覆盖
    公共无效的onCreate（捆绑savedInstanceState）{
        super.onCreate（savedInstanceState）;
        的setContentView（R.layout.main）;
        行=的getXML（）;
        的System.out.println（线）;
    }    // ------------------------------------------------
    公共字符串的getXML（）{
        串strXML =;
        尝试{
            DefaultHttpClient的HttpClient =新DefaultHttpClient（）;
            HttpPost httpPost =新HttpPost（parsingWebURL）;
            HTT presponse HTT presponse = httpClient.execute（httpPost）;
            HttpEntity httpEntity = HTT presponse.getEntity（）;
            strXML = EntityUtils.toString（httpEntity）;
            返回strXML;
        }赶上（例外E1）{
            e1.printStackTrace（）;
        }
        返回strXML;
    }
}
 

解决方案

这不是你的code本身，它的网站，它有很多的重定向响应请求时使用移动用户代理进行。

要复制一个桌面浏览器，改变你的用户代理字符串。像这样：

 公共字符串的getXML（）{
    串strXML =;
    尝试{        最终的HttpParams PARAMS =新BasicHttpParams（）;
        HttpClientParams.setRedirecting（参数，可以真正的）;
        HttpClientParams.setCookiePolicy（参数，可以CookiePolicy.BROWSER_COMPATIBILITY）;        DefaultHttpClient的HttpClient =新DefaultHttpClient（PARAMS）;
        httpClient.getParams（）的setParameter（CoreProtocolPNames.USER_AGENT，Mozilla的/ 5.0（Windows NT的6.1; Win64的; 64; RV：23.0）的Gecko / 20131011火狐/ 23.0）。        HTTPGET HTTPGET =新HTTPGET（parsingWebURL）;        HTT presponse HTT presponse = httpClient.execute（HTTPGET）;
        HttpEntity httpEntity = HTT presponse.getEntity（）;
        strXML = EntityUtils.toString（httpEntity）;
        返回strXML;
    }赶上（例外E1）{
        e1.printStackTrace（）;
    }
    返回strXML;
}
 

I am trying to get simple HTTP response from this URL : http://realtorsipad.demowebsiteonline.net/eventsfeed.php

But surprisingly it not returning expected XML response rather returning another HTML page!

I am not being able understand what is issue.

Here is sample activity :

public class MainActivity1 extends Activity {
    String parsingWebURL = "http://realtorsipad.demowebsiteonline.net/eventsfeed.php";
    String line = "";
    Document docXML;

    /** Called when the activity is first created. */
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
        line = getXML();
        System.out.println(line);
    }

    // ------------------------------------------------
    public String getXML() {
        String strXML = "";
        try {
            DefaultHttpClient httpClient = new DefaultHttpClient();
            HttpPost httpPost = new HttpPost(parsingWebURL);
            HttpResponse httpResponse = httpClient.execute(httpPost);
            HttpEntity httpEntity = httpResponse.getEntity();
            strXML = EntityUtils.toString(httpEntity);
            return strXML;
        } catch (Exception e1) {
            e1.printStackTrace();
        }
        return strXML;
    }
}

解决方案

It's not your code per se, it's the site, it responds with a lot of redirects when the request is made with a mobile user-agent.

To replicate a desktop browser, change your user agent string. Like so:

public String getXML() {
    String strXML = "";
    try {

        final HttpParams params = new BasicHttpParams();
        HttpClientParams.setRedirecting(params, true);
        HttpClientParams.setCookiePolicy(params, CookiePolicy.BROWSER_COMPATIBILITY);

        DefaultHttpClient httpClient = new DefaultHttpClient(params);
        httpClient.getParams().setParameter(CoreProtocolPNames.USER_AGENT, "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:23.0) Gecko/20131011 Firefox/23.0");

        HttpGet httpGet = new HttpGet(parsingWebURL);

        HttpResponse httpResponse = httpClient.execute(httpGet);
        HttpEntity httpEntity = httpResponse.getEntity();
        strXML = EntityUtils.toString(httpEntity);
        return strXML;
    } catch (Exception e1) {
        e1.printStackTrace();
    }
    return strXML;
}

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