处理'/'时DataContracJsonSerializer和WriteObject

本文介绍了处理'/'时DataContracJsonSerializer和WriteObject的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

我有以下功能

 public static string Serialize<T>(T obj)
        {
            string returnVal = "";
            try
            {
                DataContractJsonSerializer serializer = new DataContractJsonSerializer(obj.GetType());
                using (MemoryStream ms = new MemoryStream())
                {
                    serializer.WriteObject(ms, obj);
                   returnVal = Encoding.UTF8.GetString(ms.ToArray());
                }
            }
            catch (Exception /*exception*/)
            {
                returnVal = "";
            }
            return returnVal;
        }

当obj包含一个字符串字段，其中包含带有'/'的字符串，例如：

when obj contains a string field which contains a string with '/' s such as :

" A4AAAAAAAAAAAAA ///////"

当调用WriteObject并稍后将其变为字符串（使用ToArray（））时，它变为（当JSON时）

when WriteObject is called and later made into a string (with ToArray()) it becomes (when JSON)

" A4AAAAAAAAAAAAA \ / \ / \ / \ / \ / \ / \ /"

我怎样才能避免这种情况，并且不为每个'\'添加'/'？

推荐答案

我建议您使用javascriptSerializer或Newtonsoft.Json，这可能优雅地解决问题。

我做了一个演示，希望它对你有用。

I suggest you use the javascriptSerializer or Newtonsoft.Json, which could solve the problem gracefully.
I have made a demo, wish it is useful to you.

class Program
    {
        static void Main(string[] args)
        {
            Product p = new Product()
            {
                Id = 1,
                Name = "Apple////"
            };
            var result = Serialize<Product>(p);
            Console.WriteLine(result);
        }
        public static string Serialize<T>(T obj)
        {
            string result = "";
            try
            {
                JavaScriptSerializer serializer = new JavaScriptSerializer();
                result = serializer.Serialize(obj);
                //JsonSerializer serializer = new JsonSerializer();
                //StringBuilder sb = new StringBuilder();
                //TextWriter tw = new StringWriter(sb);
                //serializer.Serialize(tw, obj);
                //result = sb.ToString();
            }
            catch (Exception)
            {
                result = "";
            }
            return result;
        }
    }
    public class Product
    {
        public int Id { get; set; }
        public string Name { get; set; }
}

结果。

如果您有任何疑问，请随时与我们联系。

Feel free to let me know if you have any questions.

最好的问候

亚伯拉罕

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