法调用非函数类型uilocalnotification的值迅速2

法调用非函数类型uilocalnotification的值迅速2

本文介绍了尝试创建本地通知,但出现错误“无法调用非函数类型uilocalnotification的值迅速2的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

import UIKit

class ViewController: UIViewController {

    override func viewDidLoad() {
        super.viewDidLoad()


        var dateComp:NSDateComponents = NSDateComponents()
        dateComp.year = 2015;
        dateComp.month = 11;
        dateComp.day = 20;
        dateComp.hour = 0;
        dateComp.minute = 10;
        dateComp.timeZone = NSTimeZone.systemTimeZone()

        var calendar:NSCalendar = NSCalendar(calendarIdentifier: NSGregorianCalendar)!
        var date:NSDate = calendar.dateFromComponents(dateComp)!
        //var date:NSDate = calendar.dateFromComponents(dateComp)

        var notification:UILocalNotification = UILocalNotification()
        notification.category = "FIRST_CATEGORY"
        notification.alertBody = "HI, noti "
        notification.fireDate  = date

        UIApplication.sharedApplication().scheduledLocalNotifications(notification)


        // Do any additional setup after loading the view, typically from a nib.
    }

    override func didReceiveMemoryWarning() {
        super.didReceiveMemoryWarning()
        // Dispose of any resources that can be recreated.
    }


}
//trying to create a local notification but getting error " cannot call value of non function type uilocalnotification " in swift 2 

推荐答案

您需要致电scheduleLocalNotification,而不是scheduledLocalNotifications(请注意计划不是schedule d ):

You need to call scheduleLocalNotification, not scheduledLocalNotifications (note schedule not scheduled):

UIApplication.sharedApplication().scheduleLocalNotification(notification)

这篇关于尝试创建本地通知,但出现错误“无法调用非函数类型uilocalnotification的值迅速2的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

10-23 17:13