本文介绍了URLDecoder:转义(%)模式中的非法十六进制字符 - 对于输入字符串:"< / lt; /"的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我在尝试从我的应用程序生成.PDF文件时遇到此异常。

I am getting this exception while trying to generate a .PDF file from my application.

URLDecoder: Illegal hex characters in escape (%) pattern - For input string:....

这是堆栈跟踪

java.lang.IllegalArgumentException: URLDecoder: Illegal hex characters in escape (%) pattern - For input string: "</"
    at java.net.URLDecoder.decode(Unknown Source)

这是代码

StringBuffer outBuffer = new StringBuffer();
//some values are added to outBuffer .
String pdfXmlView = URLDecoder.decode(outBuffer.toString(), "utf-8");

尝试使用解码时URLDecoder.decode()它正在抛出异常。我得到了异常的原因,它是因为outBuffer中的%字符而来的。

While trying to decode using URLDecoder.decode() it is throwing that exception. I got the cause for the exception, it is coming because of % character in outBuffer.

如果有人知道如何解决这个问题,请帮助我。

If anyone knows how to solve this problem, please help me.

谢谢。

推荐答案

我找到了这个例外背后的原因。

I found the reason behind this exception. See this link for URLDecoder

所以在调用之前,URLDecoder.decode()我这样做了......

So before calling URLDecoder.decode() i did this...

public static String replacer(StringBuffer outBuffer) {

    String data = outBuffer.toString();
    try {
        StringBuffer tempBuffer = new StringBuffer();
        int incrementor = 0;
        int dataLength = data.length();
        while (incrementor < dataLength) {
            char charecterAt = data.charAt(incrementor);
            if (charecterAt == '%') {
                tempBuffer.append("<percentage>");
            } else if (charecterAt == '+') {
                tempBuffer.append("<plus>");
            } else {
                tempBuffer.append(charecterAt);
            }
            incrementor++;
        }
        data = tempBuffer.toString();
        data = URLDecoder.decode(data, "utf-8");
        data = data.replaceAll("<percentage>", "%");
        data = data.replaceAll("<plus>", "+");
    } catch(Exception e) {
        e.printStackTrace();
    }
    return data;
}

这篇关于URLDecoder:转义(%)模式中的非法十六进制字符 - 对于输入字符串:&quot;&lt; / lt; /&quot;的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

10-22 22:44