本文介绍了如何从SQL服务器获取动态链接以提取数据？的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
Hello!
I am not getting any errors but when I run my code it doesn't pull anything from the server. It is just blank. I feel like there must be something really obvious I'm missing.
我的尝试：
What I have tried:
<?php
if(isset($_GET['id'])) {
require_once 'login1.php';
$id = null;
$conn = new mysqli($hn, $un, $pw, $db);
if($conn->connect_error) die($conn->connect_error);
$ID = mysqli_real_escape_string($conn, $_GET['id']);
$sql = "SELECT * FROM freshwater WHERE id='$id' ";
$result = mysqli_query($conn, $sql) or die("Bad Query: $sql");
$row = mysqli_fetch_array($result);
}
else {
header('Location: freshwaterlist.php');
}
?>
<html>
<head>
<title>Fish R Us - Saltwater Fish</title>
</head>
<body>
<div class="toptext"><center>
<img src="banner.png" height="300"></img></center>
</div>
<center>
<h2><?php echo $row["name"] ?></h2>
<img src="<?php echo $row["picture"] ?>"></img>
<table>
<tr>
<th>Name</th>
<th>Type</th>
<th>Quantity</th>
<th>Price</th>
</tr>
<tr>
<td><?php echo $row["name"] ?></td>
<td><?php echo $row["type"] ?></td>
<td><?php echo $row["qty"] ?></td>
<td><?php echo $row["price"] ?></td>
</tr>
</table><br>
<table class="fish-text">
<th><?php echo $row["description"] ?></th>
</center></table><br>
<button padding: 10px 24px;><a href="products.php">Return to Products List</a></button></body>
<button padding: 10px 24px;><a href="menu.php">Return to Menu</a></button>
</html>推荐答案
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