本文介绍了集团由子阵列值的数组的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
下面是一个有趣的挑战。我有子阵在以下格式的数组:
阵列
(
A =>阵列(n = 20,名称=黑猩猩)
B =>阵列(n = 40,名称=会议)
C =>阵列(n = 20,名称=王朝)
D =>阵列(n = 50,名称=巧克力)
E =>阵列(ID = 10,姓名=香蕉)
F =>阵列(n = 50,名称=幻想)
G =>阵列(n = 50,名称=足球)
)
和我想组到一个新的数组的基础上在每个子阵列的ID字段。
阵列
(
10 =>排列
(
E =>阵列(ID = 10,姓名=香蕉)
)
20 =>排列
(
A =>阵列(n = 20,名称=黑猩猩)
C =>阵列(n = 20,名称=王朝)
)
40 =>排列
(
B =>阵列(n = 40,名称=会议)
)
50 =>排列
(
D =>阵列(n = 50,名称=巧克力)
F =>阵列(n = 50,名称=幻想)
G =>阵列(n = 50,名称=足球)
)
)
谢谢!
解决方案
$ ARR =阵列();
的foreach($ old_arr为$关键=> $项)
{
$ ARR [$项目['身份证'] [$关键] = $项目;
}
ksort($改编,SORT_NUMERIC);
Here's an interesting challenge. I have an array of subarrays in the following format:
array
(
a => array ( id = 20, name = chimpanzee )
b => array ( id = 40, name = meeting )
c => array ( id = 20, name = dynasty )
d => array ( id = 50, name = chocolate )
e => array ( id = 10, name = bananas )
f => array ( id = 50, name = fantasy )
g => array ( id = 50, name = football )
)
And I would like to group it into a new array based on the id field in each subarray.
array
(
10 => array
(
e => array ( id = 10, name = bananas )
)
20 => array
(
a => array ( id = 20, name = chimpanzee )
c => array ( id = 20, name = dynasty )
)
40 => array
(
b => array ( id = 40, name = meeting )
)
50 => array
(
d => array ( id = 50, name = chocolate )
f => array ( id = 50, name = fantasy )
g => array ( id = 50, name = football )
)
)
Thanks!
解决方案
$arr = array();
foreach($old_arr as $key => $item)
{
$arr[$item['id']][$key] = $item;
}
ksort($arr, SORT_NUMERIC);
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