本文介绍了将数据集结果,赔率和均值分割为相应的中继器的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我试图将数据集分成两个中继器,左转发器的几率,右转发器的均衡。我的代码目前只是将两者分开,但我需要赔率为一方而另一方。这是我的代码。提前谢谢!



im trying to split a dataset over two repeaters, odds to left repeater, evens to right repeater. my code at the moment just divides the two, but i need odds to be one side and evens the other. here is my code. thanks in advance!

DataView pageToView = (DataView)pagedRequests.DataSource;        
        
        DataTable leftContent = pageToView.Table.Clone();

        int divide = pagedRequests.Count / 2;



        for (int i = 0; i < divide; i++)
        {
            leftContent.ImportRow(pageToView.Table.Rows[i + pagedRequests.FirstIndexInPage]);
        }

        DataTable rightContent = pageToView.Table.Clone();
        for (int i = divide; i < pagedRequests.Count; i++)
        {
            rightContent.ImportRow(pageToView.Table.Rows[i + pagedRequests.FirstIndexInPage]);
        }


        favRepeaterLeft.DataSource = leftContent;
        favRepeaterLeft.DataBind();

        favRepeaterRight.DataSource = rightContent;
        favRepeaterRight.DataBind();

推荐答案

for(int i = 0; i < pagedRequests.Count; i++)
{
   if(i == 0 || i % 2 == 0) //even
   {
      rightContent.ImportRow(pageToView.Table.Rows[i + pagedRequests.FirstIndexInPage]);
   }
   else //odd
   {
      leftContent.ImportRow(pageToView.Table.Rows[i + pagedRequests.FirstIndexInPage]);
   }
}


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10-21 01:30