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问题描述

是否有可能创造一些清洁出这个动态查询:

  @photos = Photo.within(100:原点=> [PARAMS [:纬度],则params [:经度]),除非(PARAMS [:纬度] .nil? || PARAMS [:经度] .nil)?

如果@ photos.nil?然后
  条件= String.new
  值= Array.new

  params.each_key做|关键|

    如果key =='since_id',那么
      条件<< 和,除非conditions.length == 0
      条件<< ID>?
      值<< PARAMS [关键]
    ELSIF关键=='USER_ID',那么
      条件<< 和,除非conditions.length == 0
      条件<< USER_ID =?
      值<< PARAMS [关键]
    ELSIF关键=='身份证',那么
      条件<< 和,除非conditions.length == 0
      条件<< ID =?
      值<< PARAMS [关键]
    结束
  结束

  values​​.insert(0,条件)
  @photos = Photo.limit(15).order(created_at DESC)。其中,(价值),除非values​​.nil?

结束
 

解决方案

我认为正确的方式来做到这一点是使用范围

 范围:older_than,拉姆达{|价值|其中(ID>()?,value)如果值}
适用范围:with_id,拉姆达{|价值|其中,('ID =(?)',value)如果值}
适用范围:for_user,拉姆达{|价值|其中,('USER_ID =(?)',value)如果值}
 

在后面的搜索

  @photos = Photo.within(100:原点=> [PARAMS [:纬度],则params [:经度])
          除非(PARAMS [:纬度] .nil || PARAMS?[:东经] .nil?)

@photos = Photo.with_id(PARAMS [:ID])
               .older_than(PARAMS [:since_id])
               .for_user(PARAMS [:USER_ID])
               .order(created_at DESC)
               .limit(15)
 

Is it possible to create something cleaner out of this dynamic query:

@photos = Photo.within(100, :origin => [params[:latitude], params[:longitude]]) unless (params[:latitude].nil? || params[:longitude].nil?)

if @photos.nil? then
  conditions  = String.new
  values      = Array.new

  params.each_key do |key|

    if key == 'since_id' then
      conditions << " AND " unless conditions.length == 0
      conditions << "id > ?"
      values << params[key]
    elsif key == 'user_id' then
      conditions << " AND " unless conditions.length == 0
      conditions << "user_id = ?"
      values << params[key]
    elsif key == 'id' then
      conditions << " AND " unless conditions.length == 0
      conditions << "id = ?"
      values << params[key]
    end
  end

  values.insert(0, conditions)
  @photos = Photo.limit(15).order("created_at DESC").where(values) unless values.nil?

end
解决方案

I think the right way to do it is use scopes

scope :older_than, lambda { |value| where('id > (?)', value) if value }
scope :with_id, lambda { |value| where('id = (?)', value) if value }
scope :for_user, lambda { |value| where('user_id = (?)', value) if value }

later in search

@photos = Photo.within(100, :origin => [params[:latitude], params[:longitude]]) 
          unless (params[:latitude].nil? || params[:longitude].nil?)

@photos = Photo.with_id( params[ :id ] )
               .older_than( params[ :since_id ] )
               .for_user( params[ :user_id ] )
               .order("created_at DESC")
               .limit(15)

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10-21 01:08