在Django中以小写形式显示URL

问题描述

我的模型为零售商指定了一个类别-例如-沃尔玛"

My model has a category for a retailer--example - "Walmart"

我数据库中的所有零售商均已输入首字母大写.

All of the retailers in my database have been entered with the first letter capitalized.

我试图在我的网站上显示零售商的产品列表.

I am trying to show a list of products by retailer on my site.

我的网址看起来像这样:

My url looks like so:

path('retailer-deals/<str:retailer>', deals_by_retailer, name='retailer'),

我的看法如下:

def deals_by_retailer(request,retailer):
    retailer_deals = Deal.objects.filter(retailer__company=retailer).order_by('expired','-date_added')
    retailer = retailer
    return render(request, 'deals/deal_by_retailer.html', {'retailer_deals': retailer_deals, 'retailer': retailer})

因此，如果我转到 retailer-deals/walmart ，则不会显示任何内容...

So if i go to retailer-deals/walmart nothing shows up...

但是当然 retailer-deals/Walmart 可以正常工作

我可能很挑剔-但我认为使用小写的 walmart 看起来更专业，以防万一有人输入大写版本，我想确保它可以正确填充

i might be being nitpicky--but i think it looks more professional with the lower case walmart and just in case someone goes to enter the uppercase version, i want to make sure it populates correctly

我确实看到有人提到(?i)类似问题，

I did see someone mention a (?i) for a similar problem,

，我尝试将路径更改为此:

and i tried changing my path to this:

path('(?i)retailer-deals/< str:retailer>'，Deals_by_retailer，name ='retailer')，

但这似乎不起作用....而且，如果我要列出具有相关链接的零售商，则生成的url仍将具有大写的url.

but that doesn't seem to work....and also, if i go to list the retailers with associated links--the generated url will still have the uppercase url..

推荐答案

您可以使用 iexact ，不区分大小写的完全匹配.

You can use iexact in your filter, A case-insensitive exact match.

retailer_deals = Deal.objects.filter(
        field_name__iexact=retailer).order_by('expired','-date_added')

正如许多其他人所建议的那样，最好的方法是对子弹进行此类查询，因此您将:

As many of other people suggest,the best way is to do such query with slug, so you would have:

from django.template.defaultfilters import slugify
import uuid 
class YourModel(mdoels):
     slug = models.SlugField()
     name = models.CharField(max_mength=100)

     # override the save method to have slug automatically generated
     def save(self, *args, **kwargs):
         if self.pk is None:
             slug = slugify(self.name)
             while self.__class__.objects.filter(slug=slug).exists():
                  slug = "%s-%s" % (slug,str(uuid.uuid4())[:5])
             self.slug = slug
         super(YourModel, self).save(*args, **kwargs)

您的网址将变为:

path('retailer-deals/<slug:slug>', deals_by_retailer, name='retailer'),

和您的观点:

def deals_by_retailer(request,slug):
    retailer_deals = Deal.objects.filter(retailer__slug=slug)
    ''' codes '''

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