如何生成6位数的随机优惠券号码

本文介绍了如何生成6位数的随机优惠券号码的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

亲爱的朋友们..我想生成字母数字6位数的优惠券号码。

你能解决我的问题..

请一步一步明确指出我..

我在等你的答案..

谢谢！

My dear friends ..I want to generate Alphanumeric 6 digit coupon number.
Can you solve my problem..
Please specify me clearly step by step..
I am waiting your answers..
Thanks!

推荐答案

var chars = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789";
var stringChars = new char[6];
var random = new Random();

for (int i = 0; i < stringChars.Length; i++)
{
    stringChars[i] = chars[random.Next(chars.Length)];
}

var finalString = new String(stringChars);

了解更多关于此处的随机数：

static void Main(string[] args)
        {
            string chars = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789";
            Random random = new Random();
            string result = new string(
                Enumerable.Repeat(chars, 8)
                          .Select(s => s[random.Next(s.Length)])
                          .ToArray());



        }

Function Password_GenPass( nNoChars, sValidChars )
    ' nNoChars = length of generated password
    ' sValidChars = valid characters. If zerolength-string
     '   ( "" ) then
    '     default is used: A-Z AND a-z AND 0-9

    Const szDefault = "abcdefghijklmnopqrstuvxyzABCDEFGHIJKLMNOPQRSTUVXYZ0123456789"
    Dim nCount
    Dim sRet
    Dim nNumber
    Dim nLength

    Randomize 'init random

    If sValidChars = "" Then
        sValidChars = szDefault
    End If
    nLength = Len( sValidChars )

    For nCount = 1 To nNoChars
        nNumber = Int((nLength * Rnd) + 1)
        sRet = sRet & Mid( sValidChars, nNumber, 1 )
    Next
    Password_GenPass = sRet
    Password_GenPass( 6, "" ) = & pwd &
End Function

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