问题描述
您好，
我的数据看起来像是浮动的exepmles：
a; kkkhkhk; hgvhgvhgvh; 123; t
a; bbbg; yuj; 1237
x; 25; z; t
我想计算每一行中出现;（分号）的次数。并且，当给定字符的数量大于4时，它应该将相应的行存储到文件中。
我尝试过以下代码：
awk -F';''NF == 31'$ nom'_temp2.csv'> $ nom'_temp3.csv'
它在命令行上工作但不在crontab中工作。
等待解决方案。
提前谢谢你
我尝试过：
awk -F';''NF == 31'$ nom'_temp2.csv'> $ nom'_temp3.csv'
Hello ,
I have data that look like the floowing exepmles :
a ;kkkhkhk ;hgvhgvhgvh ;123 ;t
a ;bbbg ;yuj ;1237
x ;25 ;z ;t
I want to count the occurrences of ";"(semicolon) in every line. and, when the number of the given character is above 4, it should store the corresponding line into a file .
I have tried the code below :
awk -F ';' 'NF==31' $nom'_temp2.csv' > $nom'_temp3.csv'
it did work on command line but not in crontab.
Waiting for a solution.
Thanks you in advance
What I have tried:
awk -F ';' 'NF==31' $nom'_temp2.csv' > $nom'_temp3.csv'
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