在Android / Java中的cipher.doFinal中传递什么？

问题描述

Android代码

String apiResponse = "EcUZvMif

方法：

protected void decryptDataWithAES(String apiResponse, String key) {
        try {
            es(StandardCharsets.UTF_8);


            byte[] decodedResult = Base64.decode(apiResponse, Base64.NO_WRAP);

           terSpec = new IvParameterSpec(first16ByteArray);

            SecretKeySpec skey = new SecretKeySpec(byteArray, "AES");

            Cipher cipher = Cipher.getInstance("AES/CBC/PKCS5Padding");
            cipher.init(DECRYPT_MODE, skey, ivParameterSpec);

            String decryptString = new String(cipher.doFinal(byteArray), StandardCharsets.UTF_8);
            showLog("JSON: " + decryptString);

        } catch (Exception e) {
            e.printStackTrace();

        }
    }

异常： javax.crypto.BadPaddingException：错误：1e000065：密码函数：OPENSSL_internal：BAD_DECRYPT

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推荐答案

您正在尝试解密密钥，我想您需要解密apiResponse

You are trying to decrypt the "key", I think you need to decrypt the apiResponse

此外，您需要使用与消息加密时完全相同的IV，否则您将无法解密

Also you need the exact same IV the message was encrypted with, otherwise you won't be able to decrypt

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