使用DUKPT加密技术在读卡器中生成密文？

本文介绍了使用DUKPT加密技术在读卡器中生成密文？的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

对于

 `BDK =0123456789ABCDEFFEDCBA9876543210``KSN =FFFF9876543210E00008`

生成的密文低于

  C25C1D1197D31CAA87285D59A892047426D9182EC11353C051ADD6D0F072A6CB3436560B3071FC1FD11D9F7E74886742D9BEE0CFD1EA1064C213BB55278B2F12`

我发现

For

`BDK = "0123456789ABCDEFFEDCBA9876543210"` `KSN = "FFFF9876543210E00008"`

The ciphertext generated was below

"C25C1D1197D31CAA87285D59A892047426D9182EC11353C051ADD6D0F072A6CB3436560B3071FC1FD11D9F7E74886742D9BEE0CFD1EA1064C213BB55278B2F12"`

which I found here. I know this cipher-text is based on BDK and KSN but how this 128 length cipher text was generated? What are steps involved in it or algorithm used for this? Could someone explain in simple steps. I found it hard to understand the documents I got while googled.

解决方案

Regarding DUKPT , there are some explanations given on Wiki. If that doesn't suffice you, here goes some brief explanation.

Quoting http://www.maravis.com/library/derived-unique-key-per-transaction-dukpt/

Source

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