如何从所有行的单个列值中删除前导零。

问题描述

嗨专家，





我有一张名为releasemaster的桌子



此表的数据如下：

Hi Experts,


I have a table called releasemaster

This table having data as follows:

releaseid	  clientversion	     serviceversion	                databaseversion
116	     002.091.118	       2.91.124	                   0.40
117	     002.091.108	       2.91.114	                   0.30
118	     002.091.100	       2.91.106	                   0.28

我想删除clientversion列前导零：



例如我有Clientversion （varchar字段）值为000.090.064

我想将clientversion值显示为0.90.64

I want to remove the clientversion column leading zeros:

For example i have Clientversion(varchar field) value as 000.090.064
I want to display clientversion value as 0.90.64

 Actual column value                column value to be display 
000.123.090                                          0.123.90
090.123.090                                          90.123.90
900.080.001                                          900.80.1
900.897.000                                          900.897.0
002.009.009                                          2.9.9 

如何使用select语句获取该格式的客户端版本列值。



请帮我解决这个问题，我将非常感谢。

How can i get the client version column value in that format by using the select statement.

Please help me out with this issue , i will appreciate you.

推荐答案

select release_id,
convert(varchar, convert(int, PARSENAME(clientversion,3))) + '.' +
convert(varchar, convert(int, PARSENAME(clientversion,2))) + '.' +
convert(varchar, convert(int, PARSENAME(clientversion,1))) as ClientVersion,
serviceversion,
databaseversion from releasemaster

DECLARE @strCV [nvarchar](26)
SET @strCV='002.091.118'
SELECT RIGHT(@strCV, LEN(@strCV)-PATINDEX('%.%',@strCV)+2)

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