如何在 vi 搜索中包含正斜杠 &代替

问题描述

我有一个包含字符串 usrbin 的文件.我想搜索 usrbin 并将其替换为 /usr/bin/.

I have a file that contains the string usrbin. I want to search for usrbin and replace it with /usr/bin/.

我尝试了 :%s/usrbin/usr/bin/g，但显示错误 E488: Trailing characters.

I tried :%s/usrbin/usr/bin/g, but it's showing error E488: Trailing characters.

如何在搜索和替换中包含正斜杠?

How do I include a forward slash in a search and replace?

推荐答案

这里有两种方法:

• 转义 / 这是默认的替代分隔符::s/usrbin/\/usr\/bin
• 使用另一个替代分隔符，例如，使用散列 # 字符::s#usrbin#/usr/bin.请注意，有些字符不能用作分隔符:"、\、|

• escape the / which is the default substitute separator: :s/usrbin/\/usr\/bin
• use another substitute separator, e.g., using the hash # character: :s#usrbin#/usr/bin. Note that there are characters that you can't use as a separator: ", \, |

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