XmlNodeList中

问题描述

我知道我很亲近，而且我错过了一些愚蠢明显的东西......

I know I'm close, and I'm missing something stupidly obvious.....

我正试图让我的程序读取里面的每个项目我的XML文档的一部分。以下是一个示例：

I'm trying to get my program to read each item inside a section of my XML document. Here is an example:

<SQLScript>
   <Build73>
      <SQL FileName="Build_74.sql"/>
      <SQL FileName="Build_80.sql" />  
      <SQL FileName="Build_75.sql" />       
   </Build73>	
</SQLScript>

我正在尝试（现在）让程序显示每个SQL文件名item（Build_x.sql）。这是我最近的尝试：

I'm trying to (for now) get the program to display the SQL FileNames for each item (Build_x.sql). This has been my latest attempt:

public static void Upgrade(string db_Build, string sw_Build)
        {
            //find and open the the correct xml file
            XmlDocument upgradeDoc = new XmlDocument();
            upgradeDoc.Load(@"C:\Users\Tim\Desktop\C# Projects\Upgrade\DB_Upgrade\DB_Upgrade\bin\XML Docs\Build87.xml");
            //var SQLScript = upgradeDoc.SelectSingleNode($"/SQLScript/section[@name='{db_Build}']");


            XmlNodeList nodes = upgradeDoc.SelectNodes($"//SQLScript/{db_Build}");

            foreach(XmlNode i in nodes)
            {
                Console.WriteLine(i.Value.ToString());
            }

            

        }

我非常强烈地认为问题在于我的XMLNodeList创建行，特别是在文件路径。任何人都可以就哪些内容错误提供一些建议，或者我可以在哪里阅读（有更好的例子）？
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I feel pretty strongly that the issue lies in my XMLNodeList creation line, specifically in the file path. Can anybody offer me some advice on what piece is wrong, or where I can read up on this (with better examples)?

推荐答案

public static void Upgrade(string db_Build, string sw_Build)
        {
            //find and open the the correct xml file
            XmlDocument upgradeDoc = new XmlDocument();
            upgradeDoc.Load(@"C:\Users\Tim\Desktop\C# Projects\Upgrade\DB_Upgrade\DB_Upgrade\bin\XML Docs\Build87.xml");
            //var SQLScript = upgradeDoc.SelectSingleNode(

这篇关于XmlNodeList中的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！