本文介绍了如何将Paging添加到正常工作的“上下文”中。的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试将分页添加到正常工作的上下文中。我从NuGet下载了PagedList。
错误代码:
I am trying to add paging to a working "Context". I have downloaded "PagedList" from NuGet.
Error Code:
An exception of type 'System.NotSupportedException' occurred in EntityFramework.SqlServer.dll but was not handled in user code
Additional information: The method 'Skip' is only supported for sorted input in LINQ to Entities. The method 'OrderBy' must be called before the method 'Skip'.
using PagedList;
using System.Data.Entity;
namespace AllIndexTables.Controllers
{
public class HomeController : Controller
{
private testContext db = new testContext();
public ActionResult Index(int? page)
{
int pageSize = 5;
int pageNumber = (page ?? 1);
return View(db.Data1.ToPagedList(pageNumber, pageSize));
}
}
}
Index.cshtml
Index.cshtml
@model IEnumerable<AllIndexTables.Models.Table1>
@using PagedList.Mvc;
@using PagedList;
<h2>Index</h2>
<center>
<table>
@foreach (var item in Model)
{
<tr> {
<td>
@item.Idt
</td>
<td>
@item.datetime0
</td>
<td>
@item.col1
</td>
<td>
@item.col2
</td>
<td>
@item.col3
</td>
</tr>
}
</table>
</center>
推荐答案
private testContext db = new testContext();
public ActionResult Index(int? page)
{
var table1 = from s in db.Data1 select s;
table1 = table1.OrderBy(s => s.Idt);
int pageSize = 5;
int pageNumber = (page ?? 1);
return View(table1.ToPagedList(pageNumber, pageSize));
}
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