本文介绍了警告消息:在"..."中:无效的因子级别,生成了NA的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我不明白为什么收到此警告消息.
I don't understand why I got this warning message.
> fixed <- data.frame("Type" = character(3), "Amount" = numeric(3))
> fixed[1, ] <- c("lunch", 100)
Warning message:
In `[<-.factor`(`*tmp*`, iseq, value = "lunch") :
invalid factor level, NA generated
> fixed
Type Amount
1 <NA> 100
2 0
3 0
推荐答案
警告消息是因为您的类型"变量已成为一个因素,而午餐"不是已定义的级别.在使数据框强制类型"为字符时,请使用stringsAsFactors = FALSE
标志.
The warning message is because your "Type" variable was made a factor and "lunch" was not a defined level. Use the stringsAsFactors = FALSE
flag when making your data frame to force "Type" to be a character.
> fixed <- data.frame("Type" = character(3), "Amount" = numeric(3))
> str(fixed)
'data.frame': 3 obs. of 2 variables:
$ Type : Factor w/ 1 level "": NA 1 1
$ Amount: chr "100" "0" "0"
>
> fixed <- data.frame("Type" = character(3), "Amount" = numeric(3),stringsAsFactors=FALSE)
> fixed[1, ] <- c("lunch", 100)
> str(fixed)
'data.frame': 3 obs. of 2 variables:
$ Type : chr "lunch" "" ""
$ Amount: chr "100" "0" "0"
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