比较两个对象数组，并删除第二个对象数组中具有相同属性值的项

问题描述

我要做的就是比较两个对象数组，并删除第二个对象数组中具有相同属性值的项目.例如:

All I need to do is compare two arrays of objects and remove items in the second one that have the same property value. For example:

var a = [{'name':'bob', 'age':22}, {'name':'alice', 'age':12}, {'name':'mike', 'age':13}];
var b = [{'name':'bob', 'age':62}, {'name':'kevin', 'age':32}, {'name':'alice', 'age':32}];

function remove_duplicates(a, b) {
    for (var i = 0, len = a.length; i < len; i++) {
        for (var j = 0, len = b.length; j < len; j++) {
            if (a[i].name == b[j].name) {
                b.splice(j, 1);
            }
        }
    }

    console.log(a);
    console.log(b);

}

console.log(a);
console.log(b);

remove_duplicates(a,b);

我不明白为什么这不起作用，而是给出了:

I cannot understand why this does not work and instead gives:

Uncaught TypeError: Cannot read property 'name' of undefined

我期望的是b中的以下内容:

What I expected was the following content in b:

[{'name':'kevin', 'age':32}];

推荐答案

FIDDLE

FIDDLE

 for (var i = 0, len = a.length; i < len; i++) { 
        for (var j = 0, len2 = b.length; j < len2; j++) { 
            if (a[i].name === b[j].name) {
                b.splice(j, 1);
                len2=b.length;
            }
        }
    }

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