我想问一下，当我按下“Y”时，我将如何添加重复功能。

本文介绍了我想问一下，当我按下“Y”时，我将如何添加重复功能。的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述 // TMA2Q3.cpp：定义控制台应用程序的入口点。 // #include stdafx.h #include stdio.h #include string.h int main（）{ int maxNumber = 0 ; printf（ 按名称和ID编制：12345 \ n ）; printf（ Class：3SPG1 \\\）; printf（ 此程序接受一组数字并执行排序和索引。\ n）; printf（ 请输入要排序的数字（最多20个）：）; scanf_s（ ％d，& maxNumber）; int * aryNumbers = NULL; int * sortedIndex = NULL; int * sortedNumbers = NULL; aryNumbers = realloc（aryNumbers，maxNumber）; sortedIndex = realloc（sortedIndex，maxNumber）; sortedNumbers = realloc（sortedNumbers，maxNumber）; for （ int i = 1 ; i< = maxNumber; i ++）{ char y [ 2 ]; itoa（i，y， 10 ）; printf（ 数字键＃％s：，& y）; scanf_s（ ％d，& aryNumbers [i - 1 ]）; sortedNumbers [i - 1 ] = aryNumbers [i - 1 ]; } printf（ 数字的原始顺序为：）; for （ int i = 0 ; i< maxNumber; i ++）{ char z [ 2 ]; itoa（aryNumbers [i]，z， 10 ）; printf（ ％s，& z）; } // 执行排序并分配 int index; for （ int i = 0 ; i< maxNumber; i ++）{ sortedIndex [i] = i + 1 ; for （ int j = 0 ; j< maxNumber; j ++）{ if （sortedNumbers [j]> sortedNumbers [i]）{ int temp = sortedNumbers [j]; sortedNumbers [j] = sortedNumbers [i]; sortedNumbers [i] = temp; sortedIndex [i] = j + 1 ; } } } printf（ \ n排序的数字是：）; for （ int i = 0 ; i< maxNumber; i ++）{ char z [ 2 ]; itoa（sortedNumbers [i]，z， 10 ）; printf（ ％s，& z）; } // 查找排序索引 for （ int i = 0 ; i < maxNumber; i ++）{ for （ int j = 0 ; j< maxNumber; j ++）{ if （aryNumbers [i] == sortedNumbers [j]）{ sortedIndex [i] = j + 1 ; } } } for （ int i = 0 ; i< maxNumber; i ++）{ char a [ 2 ]; char b [ 2 ]; char c [ 2 ]; itoa（i + 1 ，a， 10 ）; itoa（aryNumbers [i]，b， 10 ）; itoa（sortedIndex [i]，c， 10 ）; printf（ \ n编号＃％s（％s）的索引是％s，& a，& b，& c）; } printf（ \ n你想重复这个程序吗？（Y / N ）：）; char 输入; scanf_s（ ％d，& input）; return 0 ; } 我的尝试： 我从互联网上进行了研究，它的使用时间......循环，我试过几次，它无法工作......需要帮助和建议。非常感谢。解决方案 您找到的建议是正确的：在或时使用做...而循环。 将你要重复的整个代码整理一遍，它会起作用： char [ 100 ] inp; 做 { ...你的代码在这里... scanf（ ％s，inp）; } while （inp [ 0 ] == ' y' || inp [ 0 ] == ' Y'）; 返回 0 ; 引用：对不起老板，我对编程知识不足0。 这对我来说真的很难，我不明白循环如何工作。 希望你能帮助我。谢谢 A 而循环非常简单： while （a） {b; } c; 1）如果条件 a 的计算结果为true，请输入循环。 1.1）执行一个或多个陈述 b 1.2）回到（1） $ b $的测试b 2）如果条件 a 为假，则执行 c 。 还有一个 do ...而版本至少执行一次循环： 做 {b; } while （a）; c; 1）执行一个或多个语句 b 2）如果条件 a 计算结果为true，循环回（1） 3）否则，执行 c 。 br /> 所有这些都在文档中...... // TMA2Q3.cpp : Defines the entry point for the console application.//#include "stdafx.h"#include "stdio.h"#include "string.h"int main() {int maxNumber = 0;printf("Prepared by Name and ID: 12345 \n");printf("Class: 3SPG1 \n");printf("This program takes in a set of numbers and performs sorting and indexing. \n");printf("Please key in how many numbers you want to sort(max.20): ");scanf_s("%d", &maxNumber);int *aryNumbers = NULL;int *sortedIndex = NULL;int *sortedNumbers = NULL;aryNumbers = realloc(aryNumbers, maxNumber);sortedIndex = realloc(sortedIndex, maxNumber);sortedNumbers = realloc(sortedNumbers, maxNumber);for (int i = 1; i <= maxNumber; i++) {char y[2];itoa(i, y, 10);printf("Key in number #%s: ", &y);scanf_s("%d", &aryNumbers[i - 1]);sortedNumbers[i - 1] = aryNumbers[i - 1];}printf("The original order of the numbers are: ");for (int i = 0; i < maxNumber; i++) {char z[2];itoa(aryNumbers[i], z, 10);printf("%s ", &z);}//perform sorting and assignint index;for (int i = 0; i < maxNumber; i++) {sortedIndex[i] = i + 1;for (int j = 0; j < maxNumber; j++) {if (sortedNumbers[j] > sortedNumbers[i]) {int temp = sortedNumbers[j];sortedNumbers[j] = sortedNumbers[i];sortedNumbers[i] = temp;sortedIndex[i] = j + 1;}}}printf("\nThe sorted numbers are: ");for (int i = 0; i < maxNumber; i++) {char z[2];itoa(sortedNumbers[i], z, 10);printf("%s ", &z);}//find sorted indexfor (int i = 0; i < maxNumber; i++) {for (int j = 0; j < maxNumber; j++) {if (aryNumbers[i] == sortedNumbers[j]) {sortedIndex[i] = j + 1;}}}for (int i = 0; i < maxNumber; i++) {char a[2];char b[2];char c[2];itoa(i + 1, a, 10);itoa(aryNumbers[i], b, 10);itoa(sortedIndex[i], c, 10);printf("\nThe index for number #%s (%s) is %s", &a, &b, &c);}printf("\nDo you want to repeat the program?(Y/N): ");char input;scanf_s("%d", &input);return 0;}What I have tried:I had research from internet, its ask for use while...loop, I had tried few time, its cannot work...need help and advice. Many thanks. 解决方案 The advice you found is right: use a while or do...while loop.PUt one round the whole of the code you want to repeat, and it will work:char[100] inp;do { ... your code here ... scanf("%s", inp); } while (inp[0] == 'y' || inp[0] == 'Y');return 0;Quote:So sorry boss, I'm 0 knowledge on programming.It's really difficult for me, I was not understand how while loop work.Hopefully you can help me. ThanksA while loop is really simple:while (a) { b; }c;1) If the condition a evaluates to true, enter the loop.1.1) Execute the statement or statements b 1.2) Got back round to the test at (1)2) If the condition a was false, execute c instead.There is also a do ... while version which executes the loop at least once:do { b; } while (a);c;1) Execute the statement or statements b2) If the condition a evaluates to true, loop back to (1)3) Otherwise, execute c instead.All of this is in the documentation ... 这篇关于我想问一下，当我按下“Y”时，我将如何添加重复功能。的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！