如何在php中传递Sql参数？

INNER JOIN区域 ON CodeValue.Id = Area.fk_SlumId）; 如何传递这些值 ?? I written the Join Querylike$connectionInfo = array( "Database"=>"nsdf"); $conn = sqlsrv_connect($serverName, $connectionInfo); $result= sqlsrv_query($conn,"SELECT CodeValue.Name,CodeValue.Latitude,CodeValue.Longitude, Area.Type,Area.DescriptionFROM CodeValueINNER JOIN AreaON CodeValue.Id=Area.fk_SlumId");How to pass these values??推荐答案 connectionInfo = array（Database=>nsdf）; connectionInfo = array( "Database"=>"nsdf"); conn = sqlsrv_connect（conn = sqlsrv_connect( serverName，serverName, 这篇关于如何在php中传递Sql参数？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！