本文介绍了PROTOBUFF INT64检查aganist以前输入的数据c ++的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

message HealthOccurrenceCount
{
    required int64 HealthID=1; 
    required int32 OccCount=2; 
    optional bytes wci=3;
}

我想根据 HealthID ;如果已经输入 HealthID ,那么代替只是递增现有条目的 OccCount 而不是添加新条目。

I would like to add data based on HealthID; If HealthID is already entered then instead of adding a new entry, the program should instead just increment the existing entry's OccCount.

HealthOccurrenceCount objHelthOccCount;
if(objHelthOccCount.healthid() == healthID) // Is this right or do I need to iterate all the nodes?
{
    occCount++;  
    objHelthOccCount.set_occcount(occCount);  
}
else       
    occCount = 1;   

这段代码是否正确,或者转换 HealthID into string?

Is this code correct or I should convert HealthID into string?

生成的代码:

// required int64 HealthID = 1;
inline bool has_healthid() const;
inline void clear_healthid();
static const int kHealthIDFieldNumber = 1;
inline ::google::protobuf::int64 healthid() const;
inline void set_healthid(::google::protobuf::int64 value);


推荐答案

根据每个单数(必需或可选)字段有一个has_方法,如果该字段已设置,则返回true。

According to the doc there is a has_ methods for each singular (required or optional) field which return true if that field has been set.

您的代码将是:

        HealthOccurrenceCount objHelthOccCount;
        if(objHelthOccCount.has_healthid())
        {
            occCount++;  
            objHelthOccCount.set_occcount(occCount);  
        }
        else       
            occCount = 1; 

这篇关于PROTOBUFF INT64检查aganist以前输入的数据c ++的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

10-15 05:03