C ++-何时确切使用-&gt ;?错误:“->"的基本操作数具有非指针类型"BaseBond"

问题描述

得到一些真正令人困惑的错误，不确定确切原因.这是我的代码:

Getting some really confusing errors and not sure exactly why. Here is my code:

//=====================WORKS=======================
TradingBook::TradingBook(const char* yieldCurvePath, const char* bondPath)
{
//...Some stuff
    BaseBond* tradingBook[bondCount];

    for (int i=0; i < bondCount; i++)
    {
        tradingBook[i] = new CouponBond(bonds[i]);

        printf("Bond: %s\n"
           "  Price: %.3f\n"
           "  DV01: %.3f\n"
           "  Risk: %.3f\n", tradingBook[i]->getID(), tradingBook[i]->getPrice(), tradingBook[i]->getDV01(), tradingBook[i]->getRisk());
    }
}

//=================DOESNT WORK======================
//Gives Error: base operand of ‘->’ has non-pointer type ‘BaseBond’
void TradingBook::runAnalytics()
{
    for (int i=0; i < bondCount; i++)
    {
        tradingBook[i]->calcPrice(tradingBook[i]->getYield());
        tradingBook[i]->calcDV01();
        tradingBook[i]->calcRisk();

        printf("Bond: %s\n"
               "  Price: %.3f\n"
               "  DV01: %.3f\n"
               "  Risk: %.3f\n", tradingBook[i]->getID(), tradingBook[i]->getPrice(), tradingBook[i]->getDV01(), tradingBook[i]->getRisk());
    }
}

我得到的错误基本操作数->"在->的每个实例中都具有非指针类型"BaseBond"，但仅在runAnalytics()方法中. tradingBook是一个公共类变量.为什么它会在bottom方法中给我一个错误，但在构造函数中却给我一个错误呢?我不明白.

I get the error base operand of ‘->’ has non-pointer type ‘BaseBond’ at every instance of ->, but only in the runAnalytics() method. tradingBook is a public class variable. Why would it give me an error in the bottom method but not the constructor? I don't get it.

我还尝试在第二种方法中将所有tradingBook [i]-> method()更改为tradingBook [i] .method()，但这给我带来了细分错误，因此我认为这是不对的.谁能帮助我消除混乱?

I also tried changing all the tradingBook[i]->method() to tradingBook[i].method() in the 2nd method, but it gives me a segmentation fault so I figured that isn't right. Can anyone help me clear up my confusion?

如果需要，这是TradingBook的头文件:

In case it is needed, here is the header file for TradingBook:

class TradingBook
{
    public:
        TradingBook(const char* yieldCurvePath, const char* bondPath);
        double getBenchmarkYield(short bPeriods) const;

        BaseBond* tradingBook;
        int treasuryCount;
        Treasury* yieldCurve;
        int bondCount;
        void runAnalytics();

};

BaseBond是一个抽象类.它的孩子是CouponBond和ZeroCouponBond. tradingBook [i]都同时填充了这两种类型.这是BaseBond的标题:

BaseBond is an abstract class. It's children are CouponBond and ZeroCouponBond. tradingBook[i] is filled with both types. Here is the header for BaseBond:

class BaseBond{
  public:
    virtual double getPrice() = 0;
    virtual double getYield() = 0;
    virtual short getPeriods() = 0;
    virtual char* getID() = 0;
    virtual double getDV01() = 0;
    virtual double getRisk() = 0;
    virtual char* getRateType() = 0;
    virtual void calcPrice(double nyield) = 0;
    virtual double calcPriceR(double nyield) const = 0;
    virtual void calcDV01() = 0;
    virtual void calcRisk() = 0;


};

预先感谢您，stackOverFlow！

Thank you in advance, stackOverFlow!

推荐答案

原因如下:

BaseBond* tradingBook[bondCount];

构造函数中的

构造一个隐藏tradingBook的作用域变量.将整个行更改为:

in the constructor constructs a scoped variable that hides tradingBook. change that whole line to:

tradingBook = new BaseBond*[bondCount];

和行

BaseBond* tradingBook;

在标题中

BaseBond** tradingBook;

它应该可以工作.

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