本文介绍了列出第一行字段中给定特定枢轴项的第二行字段(多行字段)的优化枢轴项的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我很久以来一直在搜索这个,但仍然没有结果。说我有一个包含2行标签和1个数据变量的数据透视表,如下所示:

  Rowlabel1 Rowlabel2值和值
a A 1
B 2
C 3
d D 4
e E 5

我想能够列出 Rowlabel2 的枢轴项,给定一个特定的 Rowlabel1 ,以获取ABC循环,然后连接到ABC。无论我尝试什么,它只输出所有的枢轴项,ABCDE。



由于实际数据更复杂,因此无法手动进行。它还有3个行标签,而不是2个标签。



不知道是否有帮助,但解决方案也可以使用这些值。例如,当 letter 时返回值 的 Rowlabel2 code>是a。



感谢任何输入!

解决方案
 code> Sub getPiv()

Dim piv As PivotTable

'将此更改为任何范围,表名称您的pivotottable是
设置piv = ThisWorkbook。表格(SecondTable_Output)。范围(A3)。数据透视表

Dim r As Range
Dim dr As PivotItem

'这将捕获您的第一个条目rowlabel1 - 根据需要更改
设置dr = piv.PivotFields(1).PivotItems(1)

Dim str As String
str =

'如果项目被折叠,宏将不起作用,因此我们将showDetail设置为true以展开它
如果dr.ShowDetail = False然后
dr.ShowDetail = True
End If

与dr
'地址似乎是一个错误(?)如果有多个数据值列,
'datarange似乎将一行向下移动
如果.DataRange.Columns.Count> 1然后
'在这里我们从datarange转回到可枢纽的
的第二列Set r = .DataRange.Offset(-1, - (。DataRange.Cells(1,1).Column - 2))
Else
'这里我们从datarange转回到pivotottable
的第二列Set r = .DataRange.Offset(0, - (。DataRange.Cells(1, 1).Column - 2))
结束如果
结束

'根据需要删除
r.Select

'获取范围为
的单元格值字符串对于i = 1 To r.Rows.Count
str = str& & r.Cells(i,1)
Next i
str = Trim(str)
MsgBox str

End Sub


I searched a long time for this, but still inconclusive. Say I have a pivot table with 2 row labels and 1 data variable looking like:

Rowlabel1 Rowlabel2 Sum of value
   a          A          1
              B          2
              C          3
   d          D          4
   e          E          5

I want to be able to list the pivot items of Rowlabel2 given a particular Rowlabel1, to get "A"" B" "C" in loop, then concat into "ABC". Whatever I try, it only outputs all of the pivot items, "ABCDE".

Since the real data is more complex, it is not possible to do it manually. It also have 3 row labels rather than 2 labels.

Don't know if it would help but the solution can also make use of the values. For example, return the Rowlabel2 items whose value <= 3 when "letter" is "a".

Thanks for any input!!

解决方案
Sub getPiv()

Dim piv As PivotTable

'change this to whatever range and sheet names your pivottable is
Set piv = ThisWorkbook.Sheets("SecondTable_Output").Range("A3").PivotTable

Dim r As Range
Dim dr As PivotItem

'this captures your first entry in rowlabel1 - change as necessary
Set dr = piv.PivotFields(1).PivotItems(1)

Dim str As String
str = ""

'the macro won't work if the item is collapsed, so we set showDetail to true to expand it
If dr.ShowDetail = False Then
    dr.ShowDetail = True
End If

With dr
    'address what seems to be a bug(??) where if there are more than one data value columns,
    'the datarange appears to shift one row down
    If .DataRange.Columns.Count > 1 Then
        'here we shift back from the datarange to the 2nd column of the pivottable
        Set r = .DataRange.Offset(-1, -(.DataRange.Cells(1, 1).Column - 2))
    Else
        'here we shift back from the datarange to the 2nd column of the pivottable
        Set r = .DataRange.Offset(0, -(.DataRange.Cells(1, 1).Column - 2))
    End If
End With

'delete as necessary
r.Select

'obtain the string of cell values from the range
For i = 1 To r.Rows.Count
    str = str & " " & r.Cells(i, 1)
Next i
str = Trim(str)
MsgBox str

End Sub

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10-14 15:17