问题描述
在下面的代码中，mOnePlusTwo的计算结果为0.30000000000000004（尽管它的b $ b显示为.3）。因此，将该值与mThree（.3）进行比较会导致
为假。
发生了什么？还有什么我应该做的（除了使用小数类型切换到
）？
double mOne = .1;
double mTwo = .2;
double mThree = .3;
double mOnePlusTwo = mOne + mTwo;
bool mEqual = false;
if（mOnePlusTwo == mThree）
{
mEqual = true;
}
Console.WriteLine（" mOne =" + mOne）;
Console.WriteLine（" mTwo =" + mTwo）;
Console.WriteLine（" mThree =" + mThree）;
Console.WriteLine（" mOnePlusTwo =" + mOnePlusTwo）;
控制台。 WriteLine（" mThree == mOnePlusTwo？=" + mEqual）;
In the below code, mOnePlusTwo evaluates to 0.30000000000000004 (although it
displays as ".3"). Consequently, comparing that value to mThree (.3) results
in false.
What''s going on? Is there something else I should do (other than switch to
using decimal types)?
double mOne = .1;
double mTwo = .2;
double mThree = .3;
double mOnePlusTwo = mOne + mTwo;
bool mEqual = false;
if (mOnePlusTwo == mThree)
{
mEqual = true;
}
Console.WriteLine("mOne = " + mOne);
Console.WriteLine("mTwo = " + mTwo);
Console.WriteLine("mThree = " + mThree);
Console.WriteLine("mOnePlusTwo = " + mOnePlusTwo);
Console.WriteLine("mThree == mOnePlusTwo? = " + mEqual);
推荐答案
切换到小数并阅读这篇文章：
-
Reginald Blue
我一直希望我的电脑和我的电话一样容易使用。我的愿望成真了。我不再知道如何使用我的
电话。
- Bjarne Stroustrup（C ++的创始人）[引自2003年
国际智能用户界面会议]
Switch to decimal and read this article:
What Every Computer Scientist Should Know About Floating-Point Arithmetic
http://docs.sun.com/source/806-3568/ncg_goldberg.html
--
Reginald Blue
"I have always wished that my computer would be as easy to use as my
telephone. My wish has come true. I no longer know how to use my
telephone."
- Bjarne Stroustrup (originator of C++) [quoted at the 2003
International Conference on Intelligent User Interfaces]
这篇关于.1 + .2 = 0.30000000000000004的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！