题意:给一个无向图，给起点s,终点t,求最少拆掉几条边使得s到不了t，最多拆几条边使得s能到t
思路:
先跑一边最短路，记录最短路中最短的边数。总边数-最短边数就是第二个答案
第一个答案就是在最短路里面求最小割，也就是求最大流，然后依据最短路在建个新图。权为1。跑一边网络流
模板题。以后就用这套模板了
#include <iostream>
#include <cstdio>
#include <cstring>
#include <queue>
#include <vector>
using namespace std;
const int INF = 0x7f7f7f;
const int MAXM = 12e4+5;
const int MAXN = 2e3+5;
int n, m;
struct Edge {
int to, w, next;
}edge[MAXM];
int tot, head[MAXN];
void addedge(int u, int v, int w)
{
edge[tot].to = v;
edge[tot].w = w;
edge[tot].next = head[u];
head[u] = tot++;
edge[tot].to = u;
edge[tot].w = w;
edge[tot].next = head[v];
head[v] = tot++;
}
int dis[MAXN], vis[MAXN];
int minb[MAXN];
int spfa(int s)
{
memset(dis, 0x3f, sizeof(dis));
memset(vis, 0, sizeof(vis));
memset(minb, 0x3f, sizeof(minb));
queue<int> q;
dis[s] = 0;
minb[s] = 0;
vis[s] = 1;
q.push(s);
while(!q.empty()) {
int u = q.front(); q.pop();
vis[u] = 0;
for(int i = head[u]; ~i; i = edge[i].next) {
int v = edge[i].to, w = edge[i].w;
if(dis[v] == dis[u] + w) {
minb[v] = min(minb[v], minb[u] + 1);
if(!vis[v]) {
vis[v] = 1;
q.push(v);
}
}
if(dis[v] > dis[u] + w) {
dis[v] = dis[u] + w;
minb[v] = minb[u] + 1;
if(!vis[v]) {
vis[v] = 1;
q.push(v);
}
}
}
}
}
struct Eg {
int u, cap, rev;
Eg(int uu, int cc, int rr) {
u = uu; cap = cc; rev = rr;
}
};
vector<Eg> G[MAXN];
bool used[MAXN];
void add(int u, int v, int cap)
{
G[u].push_back(Eg(v, cap, G[v].size()));
G[v].push_back(Eg(u, 0, G[u].size()-1));
}
void build()
{
for(int i = 1; i <= n; ++i) {
for(int j = head[i]; ~j; j = edge[j].next) {
int v = edge[j].to, w = edge[j].w;
if(dis[v] - dis[i] == w) {
add(i, v, 1);
}
}
}
}
int dfs(int v, int t, int f)
{
if(v == t) return f;
used[v] = true;
for(int i = 0; i < G[v].size(); ++i) {
Eg &e = G[v][i];
if(!used[e.u] && e.cap > 0) {
int d = dfs(e.u, t, min(f, e.cap));
if(d > 0) {
e.cap -= d;
G[e.u][e.rev].cap += d;
return d;
}
}
}
return 0;
}
int max_flow(int s, int t)
{
int flow = 0;
while(1) {
memset(used, 0, sizeof(used));
int f = dfs(s, t, INF);
if(f == 0) return flow;
flow += f;
}
}
void init()
{
tot = 0;
memset(head, -1, sizeof(head));
for(int i = 0; i <= n; ++i) {
G[i].clear();
}
}
int main()
{
//freopen("in", "r", stdin);
while(~scanf("%d %d", &n, &m)) {
init();
for(int i = 0; i < m; ++i) {
int u, v, w;
scanf("%d %d %d", &u, &v, &w);
addedge(u, v, w);
}
spfa(1);
build();
int ans = max_flow(1, n);
printf("%d %d\n", ans, m-minb[n]);
}
return 0;
}