本文介绍了如何删除所有属性?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我想从数据中删除所有属性,并应用此解决方案.但是 one_entry()
(原始)和我的 one_entry2()
都不起作用,我不知道为什么.
I want to erase all attributes from data and applied this solution. However neither one_entry()
(the original) nor my one_entry2()
will work and I don't see why.
one_entry2 <- function(x) {
attr(x, "label") <- NULL
attr(x, "labels") <- NULL
}
> lapply(df1, one_entry2)
$`id`
NULL
$V1
NULL
$V2
NULL
$V3
NULL
我们如何做到这一点?
数据:
df1 <- setNames(data.frame(matrix(1:12, 3, 4)),
c("id", paste0("V", 1:3)))
attr(df1$V1, "labels") <- LETTERS[1:4]
attr(df1$V1, "label") <- letters[1:4]
attr(df1$V2, "labels") <- LETTERS[1:4]
attr(df1$V2, "label") <- letters[1:4]
attr(df1$V3, "labels") <- LETTERS[1:4]
attr(df1$V3, "label") <- letters[1:4]
> str(df1)
'data.frame': 3 obs. of 4 variables:
$ id: int 1 2 3
$ V1: int 4 5 6
..- attr(*, "labels")= chr "A" "B" "C" "D"
..- attr(*, "label")= chr "a" "b" "c" "d"
$ V2: int 7 8 9
..- attr(*, "labels")= chr "A" "B" "C" "D"
..- attr(*, "label")= chr "a" "b" "c" "d"
$ V3: int 10 11 12
..- attr(*, "labels")= chr "A" "B" "C" "D"
..- attr(*, "label")= chr "a" "b" "c" "d"
推荐答案
要删除所有属性,该如何处理
To remove all attributes, how about this
df1[] <- lapply(df1, function(x) { attributes(x) <- NULL; x })
str(df1)
#'data.frame': 3 obs. of 4 variables:
# $ id: int 1 2 3
# $ V1: int 4 5 6
# $ V2: int 7 8 9
# $ V3: int 10 11 12
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