openevent返回访问被拒绝

本文介绍了openevent返回访问被拒绝的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

我创建了活动
HANDLE h = CreateEvent(NULL, FALSE, FALSE, "eventname");
然后在另一个过程中打开它
HANDLE h1 = OpenEvent(EVENT_MODIFY_STATE, FALSE, "eventname");

我正常运行时效果很好.
但是当我在Windows服务中创建事件时，打开事件时会给出错误访问被拒绝.
有人可以对此问题表示怀疑吗?

I have created Event
HANDLE h = CreateEvent(NULL, FALSE, FALSE, "eventname");
And open it in another process
HANDLE h1 = OpenEvent(EVENT_MODIFY_STATE, FALSE, "eventname");

It work fine when I run normally.
But when I have created event in windows service it gives error Access denied while opening event.
Can anybody give sujjection to this problem

推荐答案

HANDLE WINAPI CreateEvent(
  __in_opt  LPSECURITY_ATTRIBUTES lpEventAttributes,
  __in      BOOL bManualReset,
  __in      BOOL bInitialState,
  __in_opt  LPCTSTR lpName
);

您必须传递SECURITY_ATTRIBUTES结构，以授予将调用OpenEvent的用户(或组)访问权限.

看看为C ++中的新对象创建安全描述符 [ ^ ]-它显示了如何使用SECURITY_ATTRIBUTES.

最好的问候
Espen Harlinn

You ave to pass a SECURITY_ATTRIBUTES structure granting access to the user (or a group) that will call OpenEvent.

Take a look at Creating a Security Descriptor for a New Object in C++[^] - it shows how to work with SECURITY_ATTRIBUTES.

Best regards
Espen Harlinn

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