将当前日期保存到3 Ints - C ++

问题描述

我想将当前的日，月和年节省成三个整数。我不知道该怎么做。

I would like to save the current day, month, and year into three ints. I have no idea how to do this.

int day;
int month;
int year;

推荐答案

#include <ctime>

int main() {
    time_t t = time(0);  // current time: http://cplusplus.com/reference/clibrary/ctime/time/
    struct tm * now = localtime(&t);  // http://cplusplus.com/reference/clibrary/ctime/localtime/

    // struct tm: http://cplusplus.com/reference/clibrary/ctime/tm/
    int day = now->tm_mday;
    int month = now->tm_mon + 1;
    int year = now->tm_year + 1900;
}

以上链接

• time（0）：当前时间：
  


• localtime ：
  


• struct tm ：
  



Links from above

• time(0): current time:http://cplusplus.com/reference/clibrary/ctime/time/
• localtime:http://cplusplus.com/reference/clibrary/ctime/localtime/
• struct tm:http://cplusplus.com/reference/clibrary/ctime/tm/

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