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问题描述
def funct():
x = 4
action = (lambda n: x ** n)
return action
x = funct()
print(x(2)) # prints 16
...我不太明白为什么2被自动分配给n?
... I don't quite understand why 2 is assigned to n automatically?
推荐答案
n是funct返回的匿名函数的参数.完全等同的funct定义是
n is the argument of the anonymous function returned by funct. An exactly equivalent defintion of funct is
def funct():
x = 4
def action(n):
return x ** n
return action
这种形式还有其他意义吗?
Does this form make any more sense?
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