本文介绍了使用iconv translit将UTF-8转换为CP1251的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试将字符串 aÜ
从 UTF-8 转换为 iconv.h > CP1251 ,结果得到字符串 a?
,当期望 aU
时。
I'am trying to convert string "aÜ
" from UTF-8 to CP1251 via C++ library iconv.h
using TRANSLIT and as a result I get string "a?
", when expecting "aU
".
当我使用php脚本<?php echo iconv( UTF-8, Windows-1251 // TRANSLIT,Ü);>
在此计算机上,我得到 aU
字符串。
When I use php script <?php echo iconv("UTF-8", "Windows-1251//TRANSLIT", "Ü");>
on this computer, I get "aU
" string as result.
这里是代码:
#include <cstdlib>
#include <iconv.h>
#include <locale.h>
#include <stdio.h>
#include <string.h>
#include <errno.h>
using namespace std;
int IConvert(char *buf,char *outbuf, size_t len, const char *from, const char *to)
{
iconv_t iconv_cd;
if ((iconv_cd = iconv_open(to, from)) == (iconv_t) -1) {
printf("Cannot open iconv from %s to %s\n", from, to);
return 0;
}
char *inbuf = buf;
size_t inlen = len;
size_t outlen = len;
size_t res = 0;
while (inlen > 0 && outlen > 0) {
res = iconv(iconv_cd, &inbuf, &inlen, &outbuf, &outlen);
if (res == 0)
break;
if (res == (size_t) (-1)) {
if (errno != EILSEQ && errno != EINVAL) {
iconv_close(iconv_cd);
*outbuf = '\0';
printf("Erorr %s (%s)\n", strerror(errno), from);
return 0;
} else if (inbuf < outbuf) {
iconv_close(iconv_cd);
*outbuf = '\0';
printf("Erorr %s (inbuf < outbuf)\n", strerror(errno));
return 0;
}
}
if (inlen > 0 && outlen > 0) {
*outbuf++ = *inbuf++;
inlen--;
outlen--;
}
}
iconv_close(iconv_cd);
*outbuf = '\0';
return 1;
}
int main(int argc, char** argv) {
char* line = "\u00C0a\u00DC";
char* from = (char*) malloc(strlen(from)+1);
char* to = (char*) malloc(strlen(from)+1);
strcpy(from, line);
printf("%s\n", from);
IConvert(from, to, strlen(from)+1, "UTF-8", "CP1251//TRANSLIT");
printf("%s\n", to);
return 0;
}
任何想法可能是什么问题?
Any idea what problem could be?
推荐答案
解决方案
setlocale(LC_ALL, "");
在程序开始时。是的,地区会影响音译。在德国语言环境中,Ü会音译为UE而不是U。
at the beginning of your program. Yes, the locale influences the transliteration. In a German locale Ü would be transliterated to UE not U.
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