在 mathematica 中可以对 PointSize[]、Thickness[] 进行相对大小更改吗?

问题描述

源于这个关于线条粗细和点大小设置的问题 [例如PointSize[Large}, PointSize[0.5]), 我想知道是否可以改变 PointSize[], Thickness[] 等以相对的方式?

Arising from this question regarding line thickness and point size setting [e.g. PointSize[Large}, PointSize[0.5]), I was wondering if it is feasible to change PointSize[], Thickness[] etc in a relative manner?

即为什么 PointSize[Larger] 不起作用?或者有可能以某种方式查询现有的点大小，也许可以做类似PointSize[1.25*GetPointSize[]] 的事情(如果像GetPointSize[]"这样的东西存在，我一直无法弄清楚，既不是快速查看文档，也不是快速逆向工程查看 PointSize[x])

I.e. why is it that PointSize[Larger] doesn't work? Or is possible to somehow query the existing pointsize and perhaps do something likePointSize[1.25*GetPointSize[]] (I haven't been able to figure this out if something like "GetPointSize[]" exists, neither with a quick look at the documentation, nor from a quick reverse-engineering look at PointSize[x])

推荐答案

您可以使用 PointSize 的 Style 选项形式并在值中使用 Inherited 来完成此操作:

You can do this using the Style option form of PointSize with Inherited in the value:

Graphics[{Style[{Point[{0, 0}], 
Style[{Point[{.2, 0}], 
  Style[{Point[{.4, 0}], 
    Style[{Point[{.6, 0}], 
      Style[{Point[{.8, 0}]}, PointSize -> .9 Inherited]}, 
     PointSize -> .9 Inherited]}, PointSize -> .9 Inherited]}, 
 PointSize -> .9 Inherited]}, PointSize -> .1]}, PlotRange -> 1]

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